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3 years ago

Is a triangle with the given side lengths of 15cm, 17cm, and 19cm a right triangle?

Mathematics

2 answers:

Natali5045456 [20]3 years ago

7 0

Answer:

No, it is not a right triangle.

Step-by-step explanation:

Alexandra [31]3 years ago

3 0

Lets see!
We need to use the pythagorean theorem (a^2+b^2=c^2) to check.
So..
15^2+ 17^2 = 19^2
225+ 289= 361
Hm 225 and 289 do NOT equal 361 therefore it is NOT a right triangle.

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2 years ago

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Bryan created a scale drawing of his rectangular bedroom. His drawing had dimensions of 6 inches by 8 inches. If the scale that

vlabodo [156]

Answer:

56 feet

Step-by-step explanation:

If 1 inch = 2 feet, we can first find the actual dimensions of his room by multiplying the number of inches by 2.

6(2)

= 12

8(2)

= 16

So, the actual dimensions of his room are 12 feet by 16 feet.

To find the perimeter, use the perimeter formula, P = 2l + 2w.

Plug in the length and width:

P = 2l + 2w

P = 2(12) + 2(16)

P = 24 + 32

P = 56

So, the perimeter of his actual room is 56 feet.

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2 years ago

Pick a user for me (im so indecicive) most helpful answer gets brainlist ofc also lots of points, yw!

LUCKY_DIMON [66]

Answer:

I just answered the other question you asked. Why did you ask the same question twice? Also, I said the 1st one

Step-by-step explanation:

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2 years ago

In the square below, the two semi-circles are congruent. Find the area of the shaded region. If necessary, round your answer to

Jobisdone [24]

Let's start with the area of the square
$area \: square = s \times s = 8 \times 8 = 64$
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

$area \: circle = \pi {r}^{2} = \pi \times {4}^{2} = 16\pi$
now we just subtract and our answer is

$64 - 16\pi = 64 - 16 \times (3.14) = 13.73$

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3 years ago

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Harlamova29_29 [7]

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3 years ago