Suppose that a car weighing 4000 pounds is supported by four shock absorbers Each shock absorber has a spring constant of 6500 l
1 answer:
Answer:
0.43622 seconds
0.9158 foot
-4.43 ffot/sec
Explanation:
we first find the period of oscillation
= 2π√w/gk
= 2π√4000/32x2600
= 2π√0.00481
= 2π0.0694
= 0.43622
b. we find the angular velocity
2π/T
= 2π/0.43622
= 14.41 rad/sec
we find displacement
rom the calculation in the attachment
Ф = -144.1
initial condition
1*cos(-144.1 rad)
= 0.9158 foot
initial velocity of the car
= (-1)(14.41)sin(ω(0)-144.1)
= -4.44 foot/sec
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Answer:
option (B)
Explanation:
Intensity of unpolarised light, I = 25 W/m^2
When it passes from first polarisr, the intensity of light becomes
Let the intensity of light as it passes from second polariser is I''.
According to the law of Malus
Where, θ be the angle between the axis first polariser and the second polariser.
I'' = 11.66 W/m^2
I'' = 11.7 W/m^2
Answer:
Av = 25 [m/s]
Explanation:
To solve this problem we must use the definition of speed, which is defined as the relationship between distance over time. for this case we have.
where:
Av = speed [km/h] or [m/s]
distance = 180 [km]
time = 2 [hr]
Therefore the speed is equal to:
Now we must convert from kilometers per hour to meters per second