Answer:
67 kg.
Explanation:
From the question,
Total momentum = (mass of the pilot+ mass of the helicopter)×velocity.
I = (m+M)v............................... Equation 1
Where I = Total momentum of the pilot and the helicopter, m = mass of the pilot, M = mass of the helicopter, v = velocity.
make m the subject of the equation
m = (I/v)-M.............................. Equation 2
Given: I = 7200 kg.m/s, v = 60 m/s, M = 53 kg.
Substitute these values into equation 2
m = (7200/60)-53
m = 120-53
m = 67 kg.
Hence the mass of the pilot is 67 kg
Option (D) is correct.
The balloon lands horizontally at a distance of 420 m from a point where it as released.
Explanation:
Velocity of air balloon along +X axis =10 m/s
velocity of ball=4 m/s along + X axis
the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s
time taken= 30 s
The distance traveled is given by d= v t
d= 14 (30)
d= 420 m
Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.
The pressure law states: "For a fixed mass of gas, at a constant volume, thepressure<span> (p) is directly proportional to the absolute temperature (T)."</span>
Answer:
3 m/s
Explanation:
Given:
a = 2 m/s²
Δx = 10 m
v = 7 m/s
Find: v₀
v² = v₀² + 2a (x − x₀)
(7 m/s)² = v₀² + 2 (2 m/s²) (10 m)
v₀ = 3 m/s
