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2 years ago

Anyone who wants to shw booooobs than u can see my body/cqg-fhfh-ptx

Physics

1 answer:

zlopas [31]2 years ago

7 0

The answer yes, she gladly will

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Please help me i have this due tommorrow!!!

Ronch [10]

I found this!! maybe this will help :)

8 0

2 years ago

Pls help me guys simple question

Airida [17]

Answer:

please write neater

Explanation:

can you write neater so I can answer th question but also is a equal to b

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3 years ago

A police officer is called to the scene of a car accident in his accident he sketches the scene and describes it according to hi

abruzzese [7]

Answer:

The driver was not telling the truth because it is not possible for a car to hit another car from behind and generate a force to the sides that deflects it from its path.

Explanation:

First, we analyze the driver's statement.

The driver when arriving at the curve, is collided from behind by another car and deviates from his path and crashes into a tree. For the car to go to the tree there must be a force towards the tree.

The net force that causes the car to deviate must be formed by the sum of the motion vector of the first car plus the force that is directed towards the tree.

Here we verify that a car hitting from behind will not generate a force to the sides, but will generate a force in the same direction that the car moves, forward.

7 0

3 years ago

Construct a graph of position versus time for the motion of a dog, using the data in the table below. Explain how the graph indi

Lynna [10]

Answer:

The dog is moving at a constant speed

Explanation:

Given that,

Position : 5, 10, 15, 20, 25

Time = 5. 10, 15, 20, 25

We need to draw a position time graph

Using given data

A graph of position and time shows the speed.

According to graph,

The graph indicates that the dog is moving at a constant speed because the graph is straight line.

Hence, The dog is moving at a constant speed

6 0

3 years ago

A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.25 kg to a friend standing in front of him

juin [17]

Answer:

The velocity of the student has after throwing the book is 0.0345 m/s.

Explanation:

Given that,

Mass of book =1.25 kg

Combined mass = 112 kg

Velocity of book = 3.61 m/s

Angle = 31°

We need to calculate the magnitude of the velocity of the student has after throwing the book

Using conservation of momentum along horizontal direction

$m_{b}v_{b}\cos\theta= m_{c}v_{c}$

$v_{s}=\dfrac{m_{b}v_{b}\cos\theta}{m_{c}}$

Put the value into the formula

$v_{c}=\dfrac{1.25\times3.61\times\cos31}{112}$

$v_{c}=0.0345\ m/s$

Hence, The velocity of the student has after throwing the book is 0.0345 m/s.

3 0

3 years ago

Anyone who wants to shw booooobs than u can see my body/cqg-fhfh-ptx​

Anyone who wants to shw booooobs than u can see my body/cqg-fhfh-ptx