Explain and Show the equation of line parallel to y=-1x+2 going through the point (6, 3)

Mathematics

1 answer:

lana [24]3 years ago

7 0

Answer:

y=-1x+9

Step-by-step explanation:

plug point in to y-y1=m(x-x1)

y-3=-1(x-6)

y-3=-1x+6

y=-1x+9

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Step-by-step explanation:

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3 years ago

Rufina [12.5K]

Answer: Graph D (bottom right corner)

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Explanation:

The equation y = 3x+3 is in slope intercept form y = mx+b

m = 3 = slope

b = 3 = y intercept

In this case, both the slope and y intercept are the same (though in general they tend not to be).

The positive slope value means the line goes uphill as you move from left to right. The positive y intercept means the diagonal line crosses the y axis somewhere above the horizontal x axis. Specifically, it crosses the y axis at y = 3

Graph D is the only graph that has such a line on it. Graphs A, B and C have the positive slope line where they have a negative y intercept, so we can rule them out.

You can use graphing tools such as Desmos or Geogebra to help confirm this answer. You could also make a table of values, and plot each point, to form the lines. Two points is the minimum amount needed to form any line.

4 0

3 years ago

Read 2 more answers

Find a vector equation and parametric equations for the line through the point (7,4, 5) and parallel to the vector 3i 2j-k .

aleksley [76]

Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k

parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t

Step-by-step explanation: The vector equation is a line of the form:

r = $r_{0}$ + t.v