How do viroids and pirons compare with viruses?

Transformed bacteria are plated on LB plus ampicillin to determine which cells were successfully transformed. Which part of the

mina [271]

Answer:

The gene that encodes ampicillin resistance.

Explanation:

The plasmid would contain the ampicillin resistance gene which gets expressed in the presence of ampicillin.

5 0

3 years ago

if we were to take water temperature samples from a column in the ocean, where would you expect to find the coldest water?

kap26 [50]

The deeper down you get, the colder the water is

4 0

4 years ago

In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s

lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp × 1000 =

0.305 × 0.155 × 1000 = 47 individuals will be double crossover.

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

Observed DCO / 47 = 0.7

Observed DCO = 0.7 × 47

Observed DCO ≅ 33

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0

4 years ago

huntington disease is a dominant disease caused by expansion of the trinucleotide repeat region of the htt gene that results in

Travka [436]

By haphazardly introducing a transgene harboring a disease-causing mutant variant of the HTT gene into the genome of a mouse or primate, it is possible to produce an animal model with the majority of the symptoms of this condition. Here option B is the correct answer.

Huntington's disease is an uncommon, genetic condition that results in the gradual degeneration of brain nerve cells. Huntington's illness, which frequently results in mobility, cognitive, and psychological problems, has a substantial impact on a person's functional capacities.

A DNA region known as a CAG trinucleotide repeat is involved in the HTT mutation that causes Huntington's disease. Three DNA-building building pieces that are repeated several times in a row make up this region.

Complete question:

Huntington's disease is a dominant disease caused by the expansion of the trinucleotide repeat region of the Htt gene that results in the production of a Huntingtin protein with an expanded number of glutamines. An animal model with most features of this syndrome could be created by

A - knocking in a wild-type copy of the Htt gene to a mouse or primate genome.

B - randomly inserting a transgene containing a wild-type allele of the Htt gene to a mouse or primate genome.

C - randomly inserting a transgene containing a disease-causing mutant allele of the Htt gene into a mouse or primate genome

D - knocking out one copy of the wild-type Htt gene from a mouse or primate genome.

E - knocking out both copies of the wild-type Htt gene from a mouse or primate genome.

To learn more about Huntington's disease

brainly.com/question/12572808

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3 0

2 years ago

NEED HELP DUE TODAY PLZ HELP ME I AM STUCK PLZ PLZ PLZ HELP ME!!!!

deff fn [24]

The answer is B. Light microscope

4 0

4 years ago

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