3Zn + 8HNO3 ---> 3Zn(NO3)2 + 4H2O + 2NO IF IT IS COLD AND DILUT NITRIC ACID .
IF IT IS HOT AND CONCENTRATED THEN:
Zn+ 4HNO3 ---> Zn(NO3)2 +2H2O +2NO2
The melting and boiling point depend on the strength of the ihydrogen bonds. Hydrogen bonding will cause the higher the melting and boiling points because more energy is needed to break bonds between molecules.
Hydrogen bonds affect solubility in water, molecules with hydrogen bonds dissolve better in water.
Answer:
a) cu2+ + 1Hg (l) 1Cl- equilibrium cu (s) + Hg2Cl2 (s)
b) 0.068 V.
Explanation:
A) Cu2+ + 2e- euilibrium cu (s)
Hg2Cl2 + 2e- equilibrium 2Hg (l) + 1cl-
Cell Reaction: cu2+ + 1Hg (l) 1Cl- equilibrium cu (s) + Hg2Cl2 (s)
B) To calculate the cell voltage
E = E_o Cu2+/Cu - (0.05916 V / 2) log 1/Cu2+
putting values we get
= 0.339V + (90.05916V/2)log(0.100) = 0.309V
E_cell = E Cu2+/Cu - E SCE = 0.309 V - 0.241 V = 0.068V.
Answer:
D I think the answer is D for this question
Answer:
The products are CO₂ and H₂O.
The ballanced equation is this:
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Explanation:
In any chemical reaction, where you see that you have a compound reacting only with oxygen (O₂), you are in front of combustion.
Products in combustion are always water vapor and carbon dioxide.
Take a look to the methane combustion.
CH₄ + 2O₂ → CO₂ + 2H₂O
1 mol of methane reacts with 2 moles of oxygen to form 1 mol of CO₂ and 2 moles of water.
This is the combustion for an alkene where 2 moles of the alkene reacts with 11 moles of oxygen to make water and CO₂ like this:
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
