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3 years ago

there is an ice cream shop 6 blocks north of your hotel. how many minutes will it take to walk there and back

Chemistry

1 answer:

Allushta [10]3 years ago

8 0

Answer:

This question is incomplete

Explanation:

This question is incomplete.

However, when all the required data are available, you can use the formula/steps below

Average speed/velocity (m/s) = distance (in metres) ÷ time (in seconds)

Time (in secs) = distance ÷ average speed/velocity

Kindly note that "blocks" is not a standard unit for distance measurement in science, hence the distance (since its a walking distance) must be in metres (or converted to metres if not in metres).

The distance in the formula is the distance from the hotel to the ice cream shop while the average speed is the distance covered per time as s/he walks to the ice cream shop and back. Hence, the answer gotten from the formula above will have to be multiplied by 2 (in order to get the time taken to walk to the ice cream shop and back) because the formula will only provide answer to one trip (time taken to walk to the shop).

After the multiplication mentioned above, the time in seconds should be converted to minutes by dividing the answer in seconds by 60

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Given the following data:

bagirrra123 [75]

$176.0 \; \text{kJ} \cdot \text{mol}^{-1}$

As long as the equation in question can be expressed as the sum of the three equations with known enthalpy change, its $\Delta H$ can be determined with the Hess's Law. The key is to find the appropriate coefficient for each of the given equations.

Let the three equations with $\Delta H$ given be denoted as (1), (2), (3), and the last equation (4). Let $a$ , $b$ , and $c$ be letters such that $a \times (1) + b \times (2) + c \times (3) = (4)$ . This relationship shall hold for all chemicals involved.

There are three unknowns; it would thus take at least three equations to find their values. Species present on both sides of the equation would cancel out. Thus, let coefficients on the reactant side be positive and those on the product side be negative, such that duplicates would cancel out arithmetically. For instance, $3 + (-1) = 2$ shall resemble the number of $\text{H}_2$ left on the product side when the second equation is directly added to the third. Similarly

$\text{NH}_4 \text{Cl} \; (s)$ : $-2 \; a = 1$
$\text{NH}_3\; (g)$ : $-2 \; b = -1$
$\text{HCl} \; (g)$ : $2 \; c = -1$

Thus

$a = -1/2\\b = 1/2\\c = -1/2$ and

$-\frac{1}{2} \times (1) + \frac{1}{2} \times (2) - \frac{1}{2} \times (3)= (4)$

Verify this conclusion against a fourth species involved- $\text{N}_2 \; (g)$ for instance. Nitrogen isn't present in the net equation. The sum of its coefficient shall, therefore, be zero.

$a + b = -1/2 + 1/2 = 0$

Apply the Hess's Law based on the coefficients to find the enthalpy change of the last equation.

$\Delta H _{(4)} = -\frac{1}{2} \; \Delta H _{(1)} + \frac{1}{2} \; \Delta H _{(2)} - \frac{1}{2} \; \Delta H _{(3)}\\\phantom{\Delta H _{(4)}} = -\frac{1}{2} \times (-628.9)+ \frac{1}{2} \times (-92.2) - \frac{1}{2} \times (184.7) \\\phantom{\Delta H _{(4)}} = 176.0 \; \text{kJ} \cdot \text{mol}^{-1}$

3 0

3 years ago

The nucleus of the atom contains what subatomic particle(s)? Protons only Neutrons only Electrons only Protons and neutrons Prot

lakkis [162]

Hello,

The answer is option C protons and neutrons.

Reason:

The middle of the nucleus contains the protons and the neutrons which contain the positive and electrical charges which decides the element which means option C will be your answer.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

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3 years ago

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When CO2(g) is put in a sealed container at 730 K and a pressure of 10.0 atm and is heated to 1420 K , the pressure rises to 24.

d1i1m1o1n [39]

Answer:

48%

Explanation:

Based on Gay-Lussac's law, the pressure is directly proportional to the temperature. To solve this question we must assume the temperature increases and all CO2 remains without reaction. The equation is:

P1T2 = P2T1

<em>Where Pis pressure and T absolute temperature of 1, initial state and 2, final state of the gas:</em>

P1 = 10.0atm

T2 = 1420K

P2 = ?

T1 = 730K

P2 = 10.0atm*1420K / 730K

P2 = 19.45 atm

The CO2 reacts as follows:

2CO2 → 2CO+ O2

Where 2 moles of gas react producing 3 moles of gas

Assuming the 100% of CO2 react, the pressure will be:

19.45atm * (3mol / 2mol) = 29.175atm

As the pressure rises just to 24.1atm the moles that react are:

24.1atm * (2mol / 19.45atm) = 2.48 moles of gas are present

The increase in moles is of 0.48 moles, a 100% express an increase of 1mol. The mole percent that descomposes is:

0.48mol / 1mol * 100 = 48%

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Elenna [48]

Answer:

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3 years ago

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bixtya [17]

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