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Neporo4naja [7]
2 years ago
11

Question 1

Mathematics
1 answer:
gulaghasi [49]2 years ago
8 0

Answer:

C

Step-by-step explanation:

A function is where each input has a single output.

(A) There can be a different amount of students in a class (e.g. 21 or 22) that have the same class length

(B) There can be multiple things that Mike can order with $1

(D) There can be multiple students have the same GPA

(C) There is one button for each snack item

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If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

log_3_2(5)=\frac{1}{5} k

Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

log_3_2(5)=\frac{log(5)}{log(32)}

You can express 32 as:

2^5

Using reduction of power property:

log_z(x^y)=ylog_z(x)

log(32)=log(2^5)=5log(2)

Therefore:

log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)

As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
3 years ago
Kati brought 1/4 dozen doughnuts to school. How many doughnuts did Kati bring
Vaselesa [24]

She brings 3 donuts because a dozen is 12 and 1/4 of 12 is 3.

7 0
3 years ago
Some students were asked what kinds of animals they have at home.
Nataly_w [17]

(a) Animals by popularity; Dogs, Cats, Others, Horses.

(b) If 250 students were interviewed, 20 students have other pets.

(c) No, it was incorrect.

Step-by-step explanation:

Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;

1. Dogs - 67%,

2. Cats - 20%

3. Others - 8%,

4. Horses - 1%.

None is not included in this list.

Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.

8% of 250 = \frac{8}{100} × 250 = 0.08 × 250 = 20.

So 20 students had other pets.

Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.

20% × x = 75, 0.2 × x = 75,

x = \frac{75}{0.2} = 375.

So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.

8 0
3 years ago
PLEASE HELP PLEASE I NEED TO KNOWW
Mazyrski [523]

Answer:

35.25

Step-by-step explanation:

5 0
2 years ago
Kyle entered a pie eating contest. He took 1/5 of a minute to eat 1/2 of a pie. How many pies can Kyle eat per minute. Please an
aev [14]

Answer:

I’m not sure.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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