Answer:
Current in the toroid will be 
Explanation:
We have given number of winding in rectangular toroid N = 1500
Self inductance of toroid L = 0.06 H
Magnetic energy stored in toroid 
We have to find the current in the toroid
Magnetic energy stored is equal to 
So current in the toroid will be
Answer:
= 9.8°
Explanation:
Width of one slit (a₁ ) = 1 / 1000 mm=0.001 mm = 10⁻⁶ m.
width of one slit in case 2 (a₂ ) = 1/500 =2 x 10⁻⁶ m
angular position of fringe, Sinθ = n λ /a
n is order of fringe , λ is wave length of light and a is slit aperture
So Sinθ ∝ 1 / a
Sin θ₁ /Sin θ₂ = a₂/a₁ ;
Sin20°/sinθ₂ = 2 / 1
sinθ₂ = Sin 20° / 2 = .342/2 = .171
θ₂ = 9.8 °
there many things you could do, one is try getting a cooling system, another thing is its extramly hot and you may need to tunr off your car to prevent the engine from over heating.
<span>Answer:
initial I = (m/2)L²/3 + (m/2)L²
where L = ½ the length of the rod, and the vertical half can be treated as a point mass.
initial I = mL²(1/6 + 1/2) = 2mL²/3
final I = m(2L)²/3 = 4mL²/3
Since I has doubled and momentum is conserved, ω has halved.
ω = 3.9 rad/s.
Formulaically: 2mL²/3 * 7.8rad/s = 4mL²/3 * ω</span>
