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3 years ago

How does one get 8.0 A? The answer is D

Physics

1 answer:

ra1l [238]3 years ago

6 0

I don't know why the answer is D , because I can't see the list of choices.

The only way to get 8.0 Amps is by making a serious mistake.

The current in the second picture is 4.0 Amps.

If the resistors are identical, then the effective resistance of

two resistors in parallel is 1/2 the resistance of each one.

The resistance in the second picture is 1/2 the resistance

in the first picture.

Current = (voltage) / (resistance)

Cutting the resistance in half causes the current to double.

If the current was 2.0 Amps in the first picture, it's 4.0 Amps

in the second picture.

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What is the gravitational force between a 45 kg person, and the Earth at 5.98 x 1024 kg, with a distance of

Assoli18 [71]

Answer:

C. 441 N

Explanation:

Gravitational force between two objects can by calculated by the formula

= G m₁m₂ / r² , m₁ and m₂ are masses at distance r

= ( 6.67 x 10⁻¹¹ x 45 x 5.98 x 10²⁴) / ( 6.38 x 10⁶ )²

= 44.09 x 10

= 440.9 N

= 441 N .

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3 years ago

A transport plane travelling at a steady speed of 132 ms and an altitude of 113 m, releases a parcel when it is directly above a

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Answer:

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2 years ago

A 3-kg rock is thrown upward with a force of 200 N at a location where the local gravitational acceleration is 9.79 m/s2 . Deter

expeople1 [14]

Answer: $56.87m/s^{2}$

Explanation:

If we make an analysis of the net force $F_{net}$ of the rock that was thrown upwards, we will have the following:

$F_{net}=F_{up}-W$ (1)

Where:

$F_{up}=200N$ is the force with which the rock was thrown

$W$ is the weight of the rock

Being the weight the relation between the mass $m=3kg$ of the rock and the acceleration due gravity $g=9.79m/s^{2}$ :

$W=m.g=(3kg)(9.79m/s^{2})$ (2)

$W=29.37 N$ (3)

Substituting (3) in (1):

$F_{net}=200N-29.37 N$ (4)

$F_{net}=170.63 N$ (5) This is the net Force on the rock

On the other hand, we know this force is equal to the multiplication of the mass with the acceleration, according to Newton's 2nd Law:

$F_{net}=m.a$ (6)

Finding the acceleration $a$ :

$a=\frac{F_{net}}{m}$ (7)

$a=\frac{170.63 N}{3kg}$ (8)

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2 years ago

Heights of men on a baseball team have a bell-shaped distribution with a mean of 166 cm 166 cm and a standard deviation of 5 cm

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Answer:

95 %

99.7 %

Explanation:

$\mu$ = 166 cm = Mean

$\sigma$ = 5 cm = Standard deviation

a) 156 cm and 176 cm

$166-5\times 2=156$

$166+5\times 2=176$

From the empirical rule 95% of all values are within 2 standard deviation of the mean, so about 95% of men are between 156 cm and 176 cm.

b) 151 cm and 181 cm

$166-5\times 3 =151$

$166+5\times 3=181$

The empirical rule tells us that about 99.7% of all values are within 3 standard deviations of the mean, so about 99.7% of men are between 151 cm and 181 cm.

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3 years ago

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