Answer:
a) I = (
+
) L² , b) w = (\frac{27 M}{18 m} + 2)⁻¹ Lv₀
Explanation:
a) The moment of inertia is a scalar that represents the inertia in circular motion, therefore it is an additive quantity.
The moment of inertia of a rod held at one end is
I₁ = 1/3 M L²
The moment of inertia of the mass at y = L
I₂ = m y²
The total inertia method
I = I₁ + I₂
I = \frac{1}{3} M L² + m (\frac{2}{3} L)²
I = (
+
) L²
b) The conservation of angular momentum, where the system is formed by the masses and the bar, in such a way that all the forces during the collision are internal.
Initial instant. Before the crash
L₀ = I₂ w₀
angular and linear velocity are related
w₀ = y v₀
w₀ =
L v₀
L₀ = I₂ y v₀
Final moment. After the crash
= I w
how angular momentum is conserved
L₀ = L_{f}
I₂ y v₀ = I w
substitute
m (
)² (\frac{2L}{3} v₀ = (
+
) L² w
m L³ v₀ = (
+
) L² w
m L v₀ = (
+
) w
L v₀ =
w
w = (\frac{27 M}{18 m} + 2)⁻¹ Lv₀
Explanation:
Function of distance w.r.t time :

Differentiate w.r.t time to get velocity :

Differentiate w.r.t time to get Acceleration :

<span>The angle with the positive x-axis is 120 degrees. We can assume that this angle is measured counterclockwise from the positive x-axis.
We can find the x-component of the vector.
x-component = 10 cos(120) = -5
We can find the y-component of the vector.
y-component = 10 sin(120) = 8.66
The x-component of the vector is -5 and the y-component of the vector is 8.66</span>
The answer is C why because I know it is