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prisoha [69]
3 years ago
10

It is often possible to change a hydrate into an anhydrous compound by heating it to drive off the water (dehydration). Write an

equation that shows the dehydration of manganese(II) sulfate pentahydrate . Use an asterisk to enter the dot.
Chemistry
1 answer:
aev [14]3 years ago
7 0

Answer:

MnSO4.5H2O(s) ---------> MnSO4(s) + 5H2O(g)

Explanation:

The dehydration of a hydrate implies that the water of crystallization is lost. Water of crystallization is included in the crystal structure as it is formed and is incorporated into the structure of the compound.

Now the equation for the dehydration of manganese(II) sulfate pentahydrate is;

MnSO4.5H2O(s) ---------> MnSO4(s) + 5H2O(g)

The  MnSO4 is now said to be anhydrous.

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8 0
3 years ago
Why melting and boiling points can be used as a way to check purity?​
jekas [21]

Answer: Let's see why

Pure solid and liquid compounds possess sharp melting and boiling points. Therefore, melting and boiling points of a compound can be used as a criteria of purity. ... Sometimes during cooling minute quantity of the substance (solid which is being purified) is added to the solution to facilitate the initial crystallisation.

Explanation:

6 0
3 years ago
A 0.01 M aqueous NaOH solution has a hydroxide concentration of ————— M?
MA_775_DIABLO [31]

Answer:

Has a hydroxide concentration of 0.01M

Explanation:

When NaOH dissociates, it gives 1mol Na+ and 1mol OH- this multiplies the concentration value and we get 0.01×1= 0.01M

4 0
3 years ago
Give chemical equation representing ionisation of carbonic acid
boyakko [2]

Answer:

HCO3− + OH− ⇌ CO32− + H2O

hope it helps!!!!

6 0
3 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\
Leviafan [203]

Answer:

 4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

Explanation:

From the question we are told that

  The number of moles of  is  n =  4.90  \ mols

The formation reaction of Mg(ClO_4)_2  is

             Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2  

From the reaction we see that

   1 mole of  Mg(ClO_4)_2  is formed by 2 moles of Cl^{-} 1 mole of  Mg^{2+} and 4  O^{2-}

 This implies that

   4.90  moles of  Mg(ClO_4)_2   will produce  (2 * 4.90) moles of  Cl^{-} ,

                                                    (1 * 4.90) moles of Mg^{2+} and

                                                    (8 * 4.90) moles of  O^{2-}

So

  4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

                           

4 0
3 years ago
Read 2 more answers
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