The amount of substance present in a certain object with a given half-life in terms of h can be expressed through the equation,
A(t) = (A(o))(0.5)^(t/h)
where A(t) is the amount of substance after t years and A(o) is the original amount. In this item we are given that A(t)/A(o) is equal to 0.89. Substituting the known values,
0.89 = (0.5)(t / 5730 years)
The value of t from the equation is 963.34 years.
<em>Answer: 963 years</em>
Since there are 63.01284 grams to one mole of HNO3, then 12.5 moles would be in 450 grams of it.
Answer:
The products react to reform the original reactants
E.g. Haber process of ammonia production
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As a result, the Poles have high pressure (cold air) while the Equator has low pressure (warm air). Hot air from the Equator rises and goes toward the Poles, while colder air from the Poles lowers and moves toward the Equator, resulting in a continuous wind pattern.
