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2 years ago

12

Why melting and boiling points can be used as a way to check purity?

1 answer:

jekas [21]2 years ago

6 0

Answer: Let's see why

Pure solid and liquid compounds possess sharp melting and boiling points. Therefore, melting and boiling points of a compound can be used as a criteria of purity. ... Sometimes during cooling minute quantity of the substance (solid which is being purified) is added to the solution to facilitate the initial crystallisation.

Explanation:

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What is the total pressure exerted by a mixture containing two gases if the partial

nikdorinn [45]

Answer: 100 torr

Explanation:

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3 years ago

If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN

viktelen [127]

Answer : The concentration of $[Fe(SCN)]^{2+}$ is, $4.32\times 10^{-4}M$

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is $SCN^-$ and $Fe^{3+}$ is excess reagent.

First we have to calculate the moles of KSCN.

$\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}$

$\text{Moles of }KSCN=0.00180M\times 0.006L=1.08\times 10^{-5}mol$

Moles of KSCN = Moles of $K^+$ = Moles of $SCN^-$ = $1.08\times 10^{-5}mol$

Now we have to calculate the concentration of $[Fe(SCN)]^{2+}$

$\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}$

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

$\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M$

Thus, the concentration of $[Fe(SCN)]^{2+}$ is, $4.32\times 10^{-4}M$

7 0

2 years ago

Similar rock formations have been discovered in the United States and Portugal. These rock formations were formed at the same ti

Ray Of Light [21]

theAnswer:A

Explanation:

6 0

2 years ago

What is the force exerted if a 52kg student accelerates into their desk at 5/ms2

murzikaleks [220]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{260 \: newton}}}}}$

Explanation:

Mass ( m ) = 52 kg

Acceleration ( a ) = 5 m / s²

Force ( F ) = ?

According to Newton's second law of motion ,

$\boxed{ \sf{force = mass \times acceleration}}$

$\longrightarrow{ \sf{force = 52 \times 5}}$

$\longrightarrow{ \sf{force = 260 \: newton}}$

Hope I helped!

Best regards! :D

3 0

3 years ago

Read 2 more answers

Will the solubility of CaSO4 in 0.10 Molar CaF2 be smaller than, larger than, or the same as in pure water?

Kay [80]

Smaller than; less of it will dissolve before the solution is saturated

3 0

3 years ago