Explanation:
Rate law is defined as the rate of a reaction is directly proportional to the concentration of reactants at constant temperature.
![Rate \propto [\text{concentration of reactant}]^{n}](https://tex.z-dn.net/?f=Rate%20%5Cpropto%20%5B%5Ctext%7Bconcentration%20of%20reactant%7D%5D%5E%7Bn%7D)
= k ![[\text{concentration of reactant}]^{n}](https://tex.z-dn.net/?f=%5B%5Ctext%7Bconcentration%20of%20reactant%7D%5D%5E%7Bn%7D)
where, k = rate constant
n = order of reaction
For the given reaction, 
Hence, its rate will be as follows.
Rate = ![k[H_{2}][NO]](https://tex.z-dn.net/?f=k%5BH_%7B2%7D%5D%5BNO%5D)
Also, it is known that slowest step in a chemical reaction is the rate determining step.
Hence, for the given rate law correct reaction is as follows.
Step 1 : 
(slow)
Balancing this equation it becomes 
(slow)
Step 2: 
(fast)
Answer:
- One mole of oxygen was used in this reaction.
- Two moles of water were produced from this reaction.
Explanation:
In addition: -<em> </em><em>T</em><em>w</em><em>o</em><em> </em><em>m</em><em>o</em><em>l</em><em>e</em><em>s</em><em> </em><em>o</em><em>f</em><em> </em><em>h</em><em>y</em><em>d</em><em>r</em><em>o</em><em>g</em><em>e</em><em>n</em><em> </em><em>w</em><em>e</em><em>r</em><em>e</em><em> </em><em>u</em><em>s</em><em>e</em><em>d</em><em>.</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
That is choice A.
The products are different from the reactants.
This may be easy to see - for example when one of the products is precipitated, like when you add BaCL2 to Na2SO4. The BaSO4 formed is insoluble in water and appears as a white precipitate.
Answer:
(1.0, 1.4)
Explanation:
Graph the two equations 
and 
. The point of intersection is the solution to the system of equations.
Graph on Desmos:
