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2 answers:
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Missing detail in the text:
"<span>A small glass bead has been charged to + 25 nC "
Solution
The force exerted on a charge q by an electric field E is given by
</span>
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span>
with
, 
is the charge on the bead. We want to calculate the field at 
:
The proton has a charge of
, therefore the force exerted on it is
And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass,
, we have
The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
"<span>A small glass bead has been charged to + 25 nC "
Solution
The force exerted on a charge q by an electric field E is given by
</span>
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span>
with
The proton has a charge of
And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass,
The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
Answer:
a)
Explanation:
- Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:
- Since the car starts from rest, v₀ =0.
- We know the value of t = 5 sec., but we need to find the value of a.
- Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:
- Replacing a and t in (1):
- Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
- Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:
- Replacing v₀, at and t in (1), we have:
- Therefore, as the truck travels twice as far as the car, the right answer is a).