Answer
Given,
refractive index of film, n = 1.6
refractive index of air, n' = 1
angle of incidence, i = 35°
angle of refraction, r = ?
Using Snell's law
n' sin i = n sin r
1 x sin 35° = 1.6 x sin r
r = 21°
Angle of refraction is equal to 21°.
Now,
distance at which refractive angle comes out
d = 2.5 mm
α be the angle with horizontal surface and incident ray.
α = 90°-21° = 69°
t be the thickness of the film.
So,
t = 2.26 mm
Hence, the thickness of the film is equal to 2.26 mm.
Answer:
Explanation:
We are given that
Distance between plates=d=2.2 cm=
Using
We have to find the magnitude of E in the region between the plates.
We know that the electric field for parallel plates
Where
Substitute the values
Hence, the magnitude of E in the region between the plates=
Answer:
the speed of the car at the top of the vertical loop
the magnitude of the normal force acting on the car at the top of the vertical loop
Explanation:
Using the law of conservation of energy ;
The magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as: