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Nana76 [90]
3 years ago
13

Hat processes lead to glacial erosion ?

Physics
1 answer:
azamat3 years ago
8 0
Yes......................
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A big box of sausages (30 kg) are lifted from the ground to the top shelf of the freezer. If the box is lifted at a constant spe
morpeh [17]

Answer:

The work done by gravity moving the box up is -514.5 Joules.

Explanation:

The gravity acts in the direction of the displacement, which in this case is negative (ground - top shelf), and so the resulting work is negative. The work is calculated as:

W_g = mg\Delta h = 30kg\cdot 9.8\frac{m}{s^2}\cdot(0-1.75)m=-514.5J

The work done by gravity moving the box up is -514.5 Joules.


4 0
3 years ago
How are wavelength and frequency related for a wave moving at a constant speed?
soldier1979 [14.2K]
Mathematically, to compute for the wavelength, λ,  we have

\lambda = \frac{v}{f}

where v is the velocity and f is the frequency.
As we can see here, given that velocity is constant, wavelength increases as frequency decreases. This shows that wavelength is inversely proportional to frequency. 

Answer: Wavelength and frequency are inversely related to each other.
6 0
3 years ago
3. The figure below shows the motion of a car. It starts from the origin, O travels 8m
Nuetrik [128]

Answer:

i. -4m

ii. 20m

Explanation:

The car travels 8m to the east, then travels 12m to the west which is the opposite of the east. Going west, the car travels 8m back to the origin point and then another 4m due west to make 12m. The displacement from the origin point is -4 (the negative sign shows the direction because displacement is a vector quantity)

Total distance = 8m going east + 8m back to origin + 4m west = 20m

4 0
3 years ago
A fighter bomber is making a bombing run flying horizontally at 500 knots (256m/s) at an altitude of 100.0m.
Jobisdone [24]

Answer:

<em>(a) t = 4.52 sec</em>

<em>(b) X = 1,156.49 m</em>

Explanation:

<u>Horizontal Launching </u>

If an object is launched horizontally, its initial speed is zero in the y-coordinate and the horizontal component of the velocity v_o remains the same in time. The distance x is computed as .

\displaystyle x=v_o.t

(a)

The vertical component of the velocity v_y starts from zero and gradually starts to increase due to the acceleration of gravity as follows

v_y=gt

This means the vertical height is computed by

\displaystyle h=h_o-\frac{gt^2}{2}

Where h_o is the initial height. Our fighter bomber is 100 m high, so we can compute the time the bomb needs to reach the ground by solving the above equation for t knowing h=0

\displaystyle t=\sqrt{\frac{2h_o}{g}}

\displaystyle t=\sqrt{\frac{2(100)}{9.8}}=4.52\ sec

(b)

We now compute the horizontal distance knowing v_o=256\ m/s

\displaystyle x=(256).(4.52)

X=1,156.49\ m

4 0
3 years ago
A cat is on a 1.5 m high table and jumps at a 37 angle with a speed of 10 m/s. how far horizontally from the edge of the table d
Kaylis [27]
The answer is 11.51 meters (:
8 0
3 years ago
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