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sammy [17]
3 years ago
10

Help with 3 & 4 please !!!

Mathematics
1 answer:
ra1l [238]3 years ago
7 0

Answer:

the answer of 3 is probably (c)

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tankabanditka [31]

Answer:

Hey If you get the answer can you help me bro

Step-by-step explanation:

I am not understanding that either

6 0
2 years ago
Round your answers to one decimal place, if necessary.
MA_775_DIABLO [31]

Answer:

Mean=12.5

Median=13

Step-by-step explanation:

What you do for the mean is you add all the numbers together to get 75.

You will then divide it by 6 because there are 6 numbers to get 12.5 as your answer.

The median all you do is find the middle number. The middle numbers are 12 and 14. You will take 12 and 14 and add them together to get 26.

You will then divide it by 2 to get 13 as your answer.

8 0
3 years ago
Read 2 more answers
A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11. Use the TI-84 Plus calculator. (a) I
sukhopar [10]

Answer:

a) We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

b) There is a 15.97% probability that x will be between 54 and 55.

c) The 47th percentile of x is X = 52.877.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

A sample of size 45 will be drawn from a population with mean 53 and standard deviation 11.

This means that \mu = 53.

We have to find the standard deviation of the sample, that is:

\sigma = \frac{11}{\sqrt{45}} = 1.64

(a) Is it appropriate to use the normal distribution to find probabilities for x?

We have the standard deviation and the mean, so it is appropriate to use the normal distribution to find probabilities for x.

(b) Find the probability that x will be between 54 and 55.

This is the pvalue of the Z score when X = 55 subtracted by the pvalue of the Z score when X = 54.

X = 55

Z = \frac{X - \mu}{\sigma}

Z = \frac{55 - 53}{1.64}

Z = 1.22

Z = 1.22 has a pvalue of 0.88877.

X = 54

Z = \frac{X - \mu}{\sigma}

Z = \frac{54 - 53}{1.64}

Z = 0.61

Z = 0.61 has a pvalue of 0.72907.

So, there is a 0.88877 - 0.72907 = 0.1597 = 15.97% probability that x will be between 54 and 55.

(c) Find the 47th percentile of x. Round the answer to at least two decimal places.

This is the value of X when Z has a pvalue of 0.47;

This is between Z = -0.07 and Z = -0.08. So we use Z = -0.075.

Z = \frac{X - \mu}{\sigma}

-0.075 = \frac{X - 53}{1.64}

X = 52.877

The 47th percentile of x is X = 52.877.

8 0
3 years ago
10 POINTS!
aksik [14]

Answer:

C

Step-by-step explanation:

3 0
3 years ago
91% of what is 108?
goblinko [34]
The answer is 84.26.
6 0
3 years ago
Read 2 more answers
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