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mr_godi [17]
3 years ago
8

5/6 × 10/11 44/65× 32/43​

Mathematics
2 answers:
jasenka [17]3 years ago
8 0

Answer:

Step-by-step explanation:

5/6  *  10/11 = 0.757575758

44/65  *  32/43 =  0.503756708

Is that all you need?

Troyanec [42]3 years ago
6 0

Answer:

1. ( x − 1 ) 2 ( y 2 − y − 12 ) + ( y 2 + y − 6 )   1 x − 1 − 5 x − 6

2. ( x 2 + x− 12 ) + ( x 2 − 8 x + 16 ) √ 50 1 x + 2 ⋅ 6 x + 1

Step-by-step explanation:

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Hello, could you help me with my math exercise? thank you in advance
Natali [406]

Answer:

100(x - 1)

Explanation:

Let's begin writing down everything

(X×(-11)+5)×(-9)+X-55

Now we can multiply

-9(-11X+5)+X-55

99X-45+X-55

And so we get

100X-100

Factorize 100

100(x-1)

4 0
3 years ago
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Leona [35]
X = 23

x - 7

(23) - 7 = 16

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7 0
3 years ago
A cylindrical canister contains 3 tennis balls. Its height is 8.75 inches and its radius is 1.5. The diameter of one tennis ball
Rudiy27
Find Volume of 1 tennis ball:----------------------------------------------Volume of 1 tennis ball = 4/3 x 3.14 x (2.5 ÷ 2)³
Volume of 1 tennis ball = 8.18 in³
----------------------------------------------Find Volume of 3 tennis balls:----------------------------------------------Volume of 3 tennis balls = 8.18 x 3 = 24.54 in³
----------------------------------------------Find Volume of teh cylindrical canister:----------------------------------------------Volume of the cylindrical canister = 3.14 x 1.5² x (2.5 x 3)
Volume of the cylindrical canister = 52.99 in³
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4 0
3 years ago
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What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

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= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

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Hope this helps you!

5 0
3 years ago
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Which of the following represents 32=8 x 4
cricket20 [7]
What is the context ? is it multiple choice ?
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