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3 years ago

9

When the force applied to an object is increased, how will the rate of acceleration change if the mass it is applied to remains

constant?

1 answer:

-Dominant- [34]3 years ago

7 0

Answer:

Because of the formula a = F/m

Explanation:

The force and mass affect the acceleration of the object, because of the formula above.

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Consider 3 polarizers. Polarizer 1 has a vertical transmission axis and polarizer 3 has a horizontal transmission axis. Taken to

kirill [66]

Answer:

Option D.) 0.09 I₀

Explanation:

The intensity, I, of a polarized light after passing through a polarizing filter is given by $I = I_{0} cos^{2} \theta$

$I_{0} =$ Original Intensity

$\theta =$ Angle between the direction of polarization and the axis of filter

After passing through the first polarizer, the initial intensity, $I_{o}$ is halved, i.e $I_{1} = \frac{I_{0} }{2}$

After passing through the second polarizer, the angle of polarization, θ = 30⁰

$I_{2} = I_{1} cos^{2} \theta$

$I_{2} = \frac{I_{0} }{2} cos^{2} 30\\I_{2} =\frac{3}{8} I_{0} \\I_{2} = 0.375 I_{0}$

After passing through the third polarizer, the angle of polarization, θ = 90⁰-30⁰ = 60⁰

$I_{3} = I_{2} cos^{2} \theta$

$I_{3} = 0.375I_{0} cos^{2} 60$

$I_{2} =0.09 I_{0}$

7 0

4 years ago

Light incident on a surface at an angle of 45 degrees undergoes diffused reflection. At what angle will it reflect?

Alexus [3.1K]

at any angle between -90 and 90 degrees. In the diffused reflection ,the surface is rough and the direction of light in not the same as the incident light. It can be reflected at any angle

4 0

3 years ago

Read 2 more answers

A cylindrical shell of radius 7.00 cm and length 2.21 m has its charge uniformly distributed on its curved surface. The magnitud

polet [3.4K]

Answer:

The net charge on the shell is 30x10^-9C

Explanation:

Pls see attached file

8 0

4 years ago

HEY CAN YALL HELP ME IN DIS!!

Natasha_Volkova [10]

It might me same volume

5 0

4 years ago

Calculate the first and second order angles for light of wavelength 400. nm and 700. nm of the grating contains 1.00 x 104 lines

Verdich [7]

Answer:

$23.58^{\circ}$ and $53.13^{\circ}$

$44.43^{\circ}$ , second order does not exist

Explanation:

n = Number of lines grating = $1\times10^4\ \text{Lines/cm}$

$\lambda$ = Wavelength

m = Order

Distance between slits is given by

$d=\dfrac{1}{n}\\\Rightarrow d=\dfrac{1}{1\times 10^4}\\\Rightarrow d=10^{-6}\ \text{m}$

$\lambda=400\ \text{nm}$

m = 1

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}\\\Rightarrow \theta=\sin^{-1}\dfrac{1\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=23.58^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 400\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=53.13^{\circ}$

The first and second order angles for light of wavelength 400 nm are $23.58^{\circ}$ and $53.13^{\circ}$ .

$\lambda=700\ \text{nm}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 700\times 10^{-9}}{10^{-6}}\\\Rightarrow \theta=44.43^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 700\times 10^{-9}}{10^{-6}}$

Here $\dfrac{2\times 700\times 10^{-9}}{10^{-6}}=1.4>1$ so there is no second order angle for this case.

The first order angle for light of wavelength 700 nm are $44.43^{\circ}$ .

Second order angle does not exist.

5 0

3 years ago