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Korolek [52]
3 years ago
5

An airplane flies in a horizontal circle of radius 500 m at a speed of 150 m/s. If the plane were to fly in the same 500 m circl

e at a speed of 300 m/s, by what factor would its centripetal acceleration change
Physics
1 answer:
elena-s [515]3 years ago
4 0

Answer:

By Factor of 4

Explanation:

The expression for centripetal acceleration is given as,

a = v²/r........... equation 1

Where a = centripetal acceleration, v = speed, r = radius of the circle.

Case 1

Given: v = 150 m/s, r = 500 m

Substitute into equation 1

a = 150²/500

a = 22500/500

a = 45 m/s².

Case 2

Given: v = 300 m/s, r = 500 m

Also substitute into equation 1

a = 300²/500

a = 180 m/s²

Factor of change of the acceleration = 180/45

Factor of change of the acceleration = 4.

Hence the acceleration will change by a factor of 4

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3 years ago
A bullet of mass 11 g strikes a ballistic pendulum of mass 1.9 kg. The center of mass of the pendulum rises a vertical distance
Ymorist [56]

Answer:

The bullet's initial speed is 243.21 m/s.

Explanation:

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We need to find the bullet's initial speed if it is assumed that the bullet remains embedded in the pendulum. Let it is v. In this case, the energy of the system remains conserved. The kinetic energy of the bullet gets converted to potential energy for the whole system. So,

\dfrac{1}{2}(m_b+m_p)V^2 =(m_b+m_p)gh\\\\V=\sqrt{2gh} \ .................(1)

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Now using conservation of momentum as :

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Put the value of V from equation (1) in above equation as :

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7 0
4 years ago
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4 0
3 years ago
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