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Afina-wow [57]
4 years ago
5

WILL GIVE BRAINLY!!!

Physics
1 answer:
Gnoma [55]4 years ago
7 0
The answer is apogee my dude
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What is the speed of a car that travels 50m in 25min? *
ArbitrLikvidat [17]

Answer:

the speed is 2

Explanation:

speed= distance/ time

speed= 50/25

= 2

hope this helps!

4 0
3 years ago
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A speeder is pulling directly away and increasing his distance from a police car that is moving at 24 m/s with respect to the gr
iogann1982 [59]
2,062,305 2,062,305 <span>2,062,305</span>
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3 years ago
How do you think overpumping groudwater is related to the formation of sinkholes?
vladimir2022 [97]
Ground water keept the ground at a stable level when it is gone the cavern it was in has no support and is at risk of callaps
3 0
4 years ago
A 2430 pound roller coaster starts from rest and is launched such that it crests a 105 ft high hill with a speed of 59 mph. The
Rudik [331]

Answer:

Explanation:

Given

Weight of roller coaster is W=2430\ pound

mass of roller coaster m=\frac{W}{g}=\frac{2430}{32.2}=75.45

Distance traveled by roller coaster d=396\ ft

drag force f_d=85\ pounds

velocity at top v=59 mph\approx 86.53\ ft/s

Suppose E is the initial energy

Conserving Energy at bottom and top

E=\frac{1}{2}mv^2+mgh+f_d\cdot d

E=0.5\times 75.45\times 86.53^2+2430\times 105+85\times 396

E=2.9\times 10^5\ foot-pound

5 0
3 years ago
A man walking on a tightrope carries a long a pole which has heavy items attached to the two ends. If he were to walk the tight-
katen-ka-za [31]

Answer:

 I_weight = M L²

this value is much larger and with it it is easier to restore balance.I

Explanation:

When man walks a tightrope, he carries a linear velocity, this velocity is related to the angular velocity by

            v = w r

For man to maintain equilibrium needs the total moment to be zero

             ∑τ = I α

              S  τ = 0

The forces on the home are the weight of the masses, the weight of the man and the support on the rope, the latter two are zero taque the distance to the center of rotation is zero.

Therefore the moment of the masses and the open is the one that must be zero.

If the man carries only the bar, we could approximate it by two open one on each side of the axis of rotation formed by the free of the rope

              I = ⅓ m L² / 4

As the length of half the length of the bar and the mass of the bar is small, this moment is small, therefore at the moment if there is some imbalance it is difficult to recover.

If, in addition to the opening, each of them carries a specific weight, the moment of inertia of this weight is

             I_weight = M L²

this value is much larger and with it it is easier to restore balance.

5 0
3 years ago
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