Answer:
resistor R₂ has the lowest current density
Explanation:
The current density is
j = I / A
now let's analyze each case
a) R₂ has an area 2A₀ and a length L₀ that R₁
b) R₃ has an area Ao and a length 3L₀ what R₁
we can see that all the area is given in relation to the resistance R₁
the current density in R₁ is
j₁ = I / A₀
the current density in R₂
j₂ = I / 2A₀
j₂ 2 = ½ I/A₀
the current density in R₃
j₃ = I / A₀
j₂ < j₁ = j₃
therefore resistor R₂ has the lowest current density
Answer:
longer for less massive stars.
Explanation:
A star is a giant astronomical or celestial object that is comprised of a luminous sphere of plasma, binded together by its own gravitational force.
It is typically made up of two (2) main hot gas, Hydrogen (H) and Helium (He).
Some of the examples of stars are Canopus, Sun (closest to the Earth), Betelgeus, Antares, Vega etc.
Generally, the time taken for the collapse of an interstellar cloud fragment to the period (time) when a main-sequence star is given birth to, is usually longer for less massive stars.
This ultimately implies that, stars that are not so massive or big in size are transformed from interstellar cloud fragment to a main-sequence star is lesser.
An element's "Atomic number" IS the number of protons
in the nucleus of each atom of the element.
If an element's Atomic number is 25, then it must follow ...
as the night follows the day ... that each atom of this element
has 25 protons in its nucleus. If it has a different number of
protons in its nucleus, then it's an atom of a different element.
Answer:
Explanation:
The computation of acceleration of the particle down the slope is shown below:-
data provided in the question
Particle of mass = 1.3 kg i,e sliding down
Inclined = 30 to the horizontal
based on the above information
Force is given by
............ 1
and sliding force is given by
= 
Hence, the acceleration of the particle down the slope is 4.9 m/sec^2
Answer:
a
The free body diagram is shown on the first uploaded image
b
The tension on the rope is 
Explanation:
From the question we are told that
The mass of the box is m
The tension on the box is T
The angle at which it is pulled is 
The force produced by the strong head wind is 
At equilibrium the net force acting on the block along the horizontal axis is zero i.e
substituting values
