Answer:
Explanation:
Given data:
Number of frame is 12+ 8 = 20
Total filtrate is 360 lb
we know
For 1 plate area 
Then for 20 are PLATE 
filtrate equation is given as
In the above equation only t and A is variable , all other terms are constant
Therefore we have
![\frac{t_2}{t_1}= \frac{A_1}{A_2} = [\frac{65}{105.33}]^2 = 0.36](https://tex.z-dn.net/?f=%5Cfrac%7Bt_2%7D%7Bt_1%7D%3D%20%5Cfrac%7BA_1%7D%7BA_2%7D%20%3D%20%5B%5Cfrac%7B65%7D%7B105.33%7D%5D%5E2%20%3D%200.36)
Answer:
0%
Explanation:
- The probability that both of the parents are homozygous recessive is zero.
- In our case, The gene for tallness is dominant over the gene for dwarfism
- Therefore; TT is homozygous dominant while tt is homozygous recessive and Tt is heterozygous.
- Heterozygous genotype (Tt) will exhibit a tall phenotype.
- When two parents are crossed and all the offsprings are tall then the possible genotype of the parents is either;
- Homozygous dominant for both parents or
TT x TT
2. One parent is homozygous dominant and the other is homozygous recessive.
TT x Tt
- Therefore, the probability of having both parents as homozygous recessive when all the offspring are tall is Zero.
C. that is the answer to the question
Answer:
A. Heat flows from block 1 to block 2
Explanation:
Thermal or heat energy flows when objects of different temperature come in contact. Heat naturally flows from hot objects (high temperature) to cold objects (low temperature) and will keep on flowing until an equilibrium is reached.
According to this question, two blocks of metal, which are of different temperatures, are illustrated to be in contact. Block 1 is at 60°C while Block 2 is at 25°C. Block 1 is hotter than Block 2, hence, heat will flow from block 1 to block 2.
