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stealth61 [152]
3 years ago
12

Separate this redox reaction into its balanced component half-reactions. What is the oxidation and reduction half reactions

Chemistry
2 answers:
Vilka [71]3 years ago
7 0

Answer:

The reduction reaction is: Cl₂ + 2 e⁻ ⇄ 2 Cl⁻

The oxidation reaction is: Cs ⇄ Cs⁺ + 1 e⁻

Explanation:

In a redox reaction, two half-reactions happen simultaneously. The oxidation refers to a species losing electrons. The reduction refers to a species gaining electrons.

Let's consider the following reaction.

Cl₂ + 2 Cs ⇄ 2CsCl

We can write the ionic equation.

Cl₂ + 2 Cs ⇄ 2 Cs⁺ + 2 Cl⁻

The reduction reaction is: Cl₂ + 2 e⁻ ⇄ 2 Cl⁻

We added 2 electrons to the left (electrons gained) to balance the half-reaction electrically.

The oxidation reaction is: Cs ⇄ Cs⁺ + 1 e⁻

We added 1 electron to the right (electrons lost) to balance the half-reaction electrically.

erma4kov [3.2K]3 years ago
3 0
<span>Separate this redox reaction into its component half-reactions. 
Cl2 + 2Na ----> 2NaCl 

reduction: Cl2 + 2 e- ----> 2Cl-1 
oxidation: 2Na ----> 2Na+ & 2 e- 


2) Write a balanced overall reaction from these unbalanced half-reactions: 

oxidation: Sn ----> Sn^2+ & 2 e- 
reduction: 2Ag^+ & 2e- ----> 2Ag 

giving us 
2Ag^+ & Sn ----> Sn^2+ & 2Ag </span>Steve O <span>· 5 years ago </span><span>
</span>
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Sindrei [870]

Answer:

n = 0.3 mol

Explanation:

Given data:

Volume of gas = 8.0 L

Temperature of gas = 45 °C (45+273 = 318 K)

Pressure of gas = 0.966 atm

Moles of gas present = ?

Ideal gas constant = R = 0.021 atm.L/mol.K

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Now we will put the values:

0.966 atm × 8 L = n × 0.0821 atm.L/mol.K × 318 K

7.728 atm.L = n × 26.12  atm.L/mol

7.728 atm.L / 26.12  atm.L/mol = n

n = 0.3 mol

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