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kolezko [41]
3 years ago
10

Define covalent bond.

Chemistry
2 answers:
joja [24]3 years ago
3 0
Covalent bond/ a chemical bond that involves the sharing of electron pairs between atoms
telo118 [61]3 years ago
3 0

what................

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How many carbon atoms are represented in the formula for CaMg3(CO3)4​
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The formula is for 1 Calcium, 3 Magnesium, 4 Carbon, & 12 Oxygen. The 4 after the parenthesis of (CO3) distributes to each element.

Answer : There are 4 Carbon atoms in the formula.
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Write word and balanced chemical equations to show the
Alex777 [14]

Answer:

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3 years ago
A student fires a bow and arrow in gym class and all his arrows land close to each other, but not on the bullseye. This student
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4 0
3 years ago
How many moles are there in 3.612 x 1024 formula units of Na2SO4?
vitfil [10]

Answer:

<h3>Theanswer is 6 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}  \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.612 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>6 moles</h3>

Hope this helps you

5 0
3 years ago
Sample A: 300 mL of 1M sodium chloride
yarga [219]

Answer:

sample B contains the larger density

Explanation:

Given;

volume of sample A, V = 300 mL = 0.3 L

Molarity of sample A, C = 1 M

volume of sample B, V = 145 mL = 0.145 L

Molarity of sample B, C = 1.5 M

molecular mass of sodium chloride, Nacl = 23 + 35.5 = 58.5 g/mol

Molarity is given as;

C = \frac{moles \ of \ solute, \ mol}{liters \ of \ solvent} \\\\Moles \ of \ solute \ for \ sample \ A = 1 \times 0.3 = 0.3 \ mol\\\\Moles \ of \ solute \ for \ sample \ B = 1.5 \times 0.145 = 0.2175 \ mol

The reacting mass for sample A = 0.3mol x  58.5 g/mol = 17.55 g

The reacting mass for sample B = 0.2175 mol x 58.5 g/mol = 12.72 g

The density of sample A  = \frac{mass}{volume} = \frac{17.55}{0.3} = 58.5 \ g/L

The density of sample B = \frac{mass}{volume} = \frac{12.72}{0.145} = 87.72 \ g/L

Therefore, sample B contains the larger density

5 0
2 years ago
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