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xxMikexx [17]
4 years ago
6

Gina's group classified their mineral samples based on relative hardness. They considered the minerals that have a hardness of l

ess than five as relatively soft, and those with a hardness of five or above as relatively hard. They showed their groupings in a table.
A 2 column table with 3 rows. The first column is labeled Relatively soft minerals with entries: Bornite, Chalcopyrite, Goethite. Second column is labeled Relatively hard minerals with entries: Hematite, Pyrite, Pyrrhotite.

What does Gina’s group need to do to correct the information in the table?

Bornite needs to be switched with pyrite.
Pyrite needs to be switched with goethite.
Goethite needs to be switched with pyrrhotite.
Pyrrhotite needs to be switched with hematit
Chemistry
1 answer:
Marta_Voda [28]4 years ago
3 0

Answer:

C

Explanation:

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Work the following question out on your own sheet of paper and submit a picture of your work:
valina [46]

Answer:

Heat  absorbed by water = 3985.26 j

Explanation:

Given data:

Mass of water = 75 g

Initial temperature = 20.0°C

Final temperature = 32.7°C

Specific heat of water  = 4.184 j/g.°C

Heat  absorbed by water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 32.7°C - 20°C

ΔT = 12.7 °C

Q = 75 g ×4.184 j/g.°C ×12.7 °C

Q = 3985.26 j

7 0
3 years ago
What is the concentration of OH− and pOH in a 0.00072 M solution of Ba(OH)2 at 25 ∘C? Assume complete dissociation.
Mumz [18]

Given :

0.00072 M solution of Ba(OH)_2 at 25^oC .

To Find :

The concentration of OH^-and pOH .

Solution :

1 mole of Ba(OH)_2 gives 2 moles of OH^- ions .

So , 0.00072 M mole of Ba(OH)_2 gives :

[OH^-]=2 \times 0.00072\ M

[OH^-]=0.00144\ M

[OH^-]=1.44\times 10^{-3}\ M

Now , pOH is given by :

pOH=-log[OH^-]\\\\pOH=-log[1.44\times 10^{-3}]\\\\pOH=2.84

Hence , this is the required solution .

3 0
3 years ago
What is the equilibrium membrane potential due to na ions if the extracellular concentration of na ions is 142 mm and the intrac
Ganezh [65]

The equilibrium membrane potential is 41.9 mV.

To calculate the membrane potential, we use the <em>Nernst Equation</em>:

<em>V</em>_Na = (<em>RT</em>)/(<em>zF</em>) ln{[Na]_o/[Na]_ i}

where

• <em>V</em>_Na = the equilibrium membrane potential due to the sodium ions

• <em>R</em> = the universal gas constant [8.314 J·K^(-1)mol^(-1)]

• <em>T</em> = the Kelvin temperature

• <em>z</em> = the charge on the ion (+1)

• <em>F </em>= the Faraday constant [96 485  C·mol^(-1) = 96 485 J·V^(-1)mol^(-1)]

• [Na]_o = the concentration of Na^(+) outside the cell

• [Na]_i = the concentration of Na^(+) inside the cell

∴ <em>V</em>_Na =

[8.314 J·K^(-1)mol^(-1) × 293.15 K]/[1 × 96 485 J·V^(-1)mol^(-1)] ln(142 mM/27 mM) = 0.025 26 V × ln5.26 = 1.66× 25.26 mV = 41.9 mV

4 0
3 years ago
Of metals and nonmetals which tend to be positive ions​
MA_775_DIABLO [31]

Answer:

metal atoms lose electrons to form positive ions (cations)

Explanation:

metal atoms lose electrons to form positive ions (cations ) non-metal atoms gain electrons to form negative ions (anions )

5 0
3 years ago
What is the temperature of 4.5 moles of a gas that occupies 50. mL at 1.35 atm?
devlian [24]

Answer:

T = 0.182 Kelvin

Explanation:

As we know that

PV = nRT\\

Where P is the pressure in atmospheric pressure

T is the temperature in Kelvin  

R is the gas constant  

V is the volume in liters

R = 0.08206

Substituting the given values in above equation, we get -

1.35 * \frac{50}{1000}= 4.5 * 0.08206* T\\

On rearranging, we get

T = \frac{1.35*50}{1000*0.08206*4.5} \\

T = 0.182 Kelvin

7 0
3 years ago
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