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mash [69]
3 years ago
12

What subatomic particle is specifically responsible for combining the atoms together to form a new substance?

Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
7 0
Nooooo ideas hdbddjg
Harman [31]3 years ago
4 0
That would be the electron

In covalent bonds, atoms share electrons to reach a stable amount of valence electrons

In ionic bonds, electrons are transferred from one atom to another in order to reach octets. The ions then become attracted to each other via positive and negative charges.
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What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
Fed [463]

<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

#SPJ4

3 0
1 year ago
Silver tarnish consists of silver sulfide. what is its chemical formula?
Andreyy89
<span>Ag2S Ag(silver) has a charge of 1+ S2-(Sufide has a charge 2- you need balance charge have to equal to zero so you need 2 silvers and one sulfide to have equilibrium</span>
3 0
3 years ago
Write balance complete molecular equation, ionic equation, and net ionic equations for the reactions that occur when each of the
AveGali [126]

<u>Answer:</u> The complete molecular, ionic, and net ionic equations are given below. The spectator ions are sodium and nitrate ions.

<u>Explanation:</u>

The ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

The net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation for the reaction of lead (II) nitrate and sodium sulfide follows:

Pb(NO_3)_2(aq)+Na_2S(aq)\rightarrow PbS(s)+2NaNO_3(s)

The ionic equation follows:

Pb^{2+}(aq)+2NO_3^-(aq)+2Na^+(aq)+S^{2-}(aq)\rightarrow PbS(s)+2Na^+(aq)+2NO_3^-(aq)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Pb^{2+}(aq)+S^{2-}(aq)\rightarrow PbS(s)

3 0
3 years ago
An experiment was conducted to determine the density of a rock sample. The table shows a partial record of the experiment.
mart [117]

Answer: the density of the rock

55.91g/ml

Explanation:

The density of the rock after it had being placed in the cylinder of water so the calculation should look like this:

Volume of water substract the mass of the rock:

And that is 142.5 ml - 86.59g =

Answer 55.91 g/ml

So the density of the rock is 55.91g/ml

5 0
3 years ago
A sample of sulfur dioxide (SO2) is initially at a temperature of 105C, a volume of 15 L, and a pressure of 1.5 atm. If the volu
Agata [3.3K]

The new pressure is 1.08 atm

<h3>Gas law </h3>

From the question, we are to determine the new pressure

Using the General gas equation,

\frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2}}

Where P₁ is the initial pressure

V₁ is the initial volume

T₁ is the initial temperature

P₂ is the final pressure

V₂ is the final volume

and T₂ is the final temperature

From the given information,

P₁ = 1.5 atm

V₁ = 15 L

T₁ = 105 C = 105 + 273.15 = 378.15 K

V₂ = 25 L

T₂ = 181 C = 181 + 273.15 = 454.15 K

P₂ = ?

Putting the parameters into the equation, we get

\frac{1.5 \times 15}{378.15} = \frac{P_{2} \times 25 }{454.15}

P_{2}= \frac{1.5 \times 15 \times 454.15}{25 \times 378.15}

P₂ = 1.08 atm

Hence, the new pressure is 1.08 atm

Learn more on Gas laws here: brainly.com/question/25736513

5 0
2 years ago
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