<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>
What is benzoic acid found in?
- Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
- Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.
Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.
Amount of moles of NaOH -2 × 0.025 = 0.05 mol
Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol
In this case, we can calculate the pH produced by the buffer of these two reagents, as follows


We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows




Now we must solve the equation above. This will be done using the following values

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.
NaOH volume
( 0.5 - 0.464)L
0.036L .................... 36ml
HCOOH volume
500 - 36 = 464mL
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<span>Ag2S
Ag(silver) has a charge of 1+
S2-(Sufide has a charge 2-
you need balance
charge have to equal to zero so you need 2 silvers and one sulfide
to have equilibrium</span>
<u>Answer:</u> The complete molecular, ionic, and net ionic equations are given below. The spectator ions are sodium and nitrate ions.
<u>Explanation:</u>
The ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.
The net ionic equation is defined as the equations in which spectator ions are not included.
Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.
The balanced molecular equation for the reaction of lead (II) nitrate and sodium sulfide follows:

The ionic equation follows:

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.
The net ionic equation follows:

Answer: the density of the rock
55.91g/ml
Explanation:
The density of the rock after it had being placed in the cylinder of water so the calculation should look like this:
Volume of water substract the mass of the rock:
And that is 142.5 ml - 86.59g =
Answer 55.91 g/ml
So the density of the rock is 55.91g/ml
The new pressure is 1.08 atm
<h3>Gas law </h3>
From the question, we are to determine the new pressure
Using the General gas equation,

Where P₁ is the initial pressure
V₁ is the initial volume
T₁ is the initial temperature
P₂ is the final pressure
V₂ is the final volume
and T₂ is the final temperature
From the given information,
P₁ = 1.5 atm
V₁ = 15 L
T₁ = 105 C = 105 + 273.15 = 378.15 K
V₂ = 25 L
T₂ = 181 C = 181 + 273.15 = 454.15 K
P₂ = ?
Putting the parameters into the equation, we get


P₂ = 1.08 atm
Hence, the new pressure is 1.08 atm
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