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mash [69]
3 years ago
12

What subatomic particle is specifically responsible for combining the atoms together to form a new substance?

Chemistry
2 answers:
riadik2000 [5.3K]3 years ago
7 0
Nooooo ideas hdbddjg
Harman [31]3 years ago
4 0
That would be the electron

In covalent bonds, atoms share electrons to reach a stable amount of valence electrons

In ionic bonds, electrons are transferred from one atom to another in order to reach octets. The ions then become attracted to each other via positive and negative charges.
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Draw the best lewis structure for h 2 ​ co 3 ​ and calculate the formal charge on carbon.
schepotkina [342]
The Lewis structure of Carbonic Acid (H₂CO₃) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with hydroxyl groups.

Formal Charge;
                        Formal charge is caculated as,

Formal charge  =  # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]

Formal charge on Carbon;

Formal charge  =  4 - [ 0 + 8/2]

Formal charge  =  4 - [4]

Formal charge  =  Zero

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3 years ago
Is a melting ice a physical change or a chemical change
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Chemical change because you don’t do that action physically
4 0
3 years ago
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What is the volume of 15.0 grams of H2S at STP
den301095 [7]
1 mole of any gas under STP has volume 22.4 L.
Molar mass M(H2S) = 2M(H) + M(S)= 2*1.0 +32.1=34.1 g/mol
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0.440 mol*1L/22.4L= 9.85 L 
<span> The volume of 15.0 grams of H2S at STP is 9.85 L.</span>

7 0
3 years ago
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1.How many metals, nonmetals and metalloids are there in the periodic table?
Butoxors [25]

Answer: 70 metals,17 nonmetals,metalloids 6

Explanation:

5 0
3 years ago
luminum and oxygen react according to the following equation: 4Al(s) +3O2(g) --&gt; 2Al2O3(s) What mass of Al2O3, in grams, can
Slav-nsk [51]

Answer: 8.7 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{4.6g}{27g/mol}=0.17moles

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

As oxygen is in excess, Aluminium is the limiting reagent and limits the formation of products.

According to stoichiometry:

4 moles of aluminium give = 2 moles of Al_2O_3(s)

Thus 0.17 moles of aluminium give=\frac{2}{4}\times 0.17=0.085mol

Mass of Al_2O_3=moles\times {\text {molar mass}}=0.085\times 102g/mol=8.7g

Thus the mass of Al_2O_3(s)  is 8.7 grams

8 0
3 years ago
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