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alisha [4.7K]
3 years ago
10

Which MOLECULES do cells need to get in order to function properly?

Chemistry
1 answer:
anyanavicka [17]3 years ago
8 0

Answer:

they get animal cells

Explanation:

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What is the empirical formula of a substance that contains 5.28 g of c, 0.887 g of h, and 3.52 g of o?
kicyunya [14]
Not sure but I think it is C2H4O
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3 years ago
Read 2 more answers
Which fraction contains the largest molecules?<br> A) diesel<br> B)gasoline <br> C)kerosene?
OLga [1]
The answer is A because of the shear thickness of diesel fuel
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Does the following compound contain a polyatomic ion? Na2SO4<br> Yes<br> No
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The answer is yes I believe so.
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2 years ago
A 1.28-kg sample of water at 10.0 °C is in a calorimeter. You drop a piece of steel with a mass of 0.385 kg at 215 °C into it. A
Kryger [21]

Answer:

T_{2}=16,97^{\circ}C

Explanation:

The specific heats of water and steel are  

Cp_{w}=4.186 \frac{KJ}{Kg^{\circ}C}

Cp_{s}=0.49 \frac{KJ}{Kg^{\circ}C}

Assuming that the water and steel are into an <em>adiabatic calorimeter</em> (there's no heat transferred to the enviroment), the temperature of both is identical when the system gets to the equilibrium T_{2}_{w}= T_{2}_{s}  

An energy balance can be written as

m_{w}\times Cp_{w}\times (T_{2}- T_{1})_{w}= -m_{s}\times Cp_{s}\times (T_{2}- T_{1})_{s}  

Replacing

1.28Kg\times 4.186\frac{KJ}{Kg^{\circ}C}\times (T_{2}-10^{\circ}C)= -0.385Kg\times 0.49 \frac{KJ}{Kg^{\circ}C} \times (T_{2}-215^{\circ}C)

Then, the temperature T_{2}=16,97^{\circ}C

8 0
3 years ago
3.
Vsevolod [243]

Answer:

2 half-lives=0.8

6 half-lives= 0.05

Explanation

Half-lives are constant and always decrease by half, implying that the concentration decreases by half at a consistent rate.

3.2/2= 1.6/2= 0.8 is two half-lives

3.2/2= 1.6/2= 0.8/2= 0.4/2= 0.2/2= 0.1/2=0.05 is six half-lives

3 0
2 years ago
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