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3 years ago

What happens to the gas particles in an an inflated ball when it gets a hole? why?

Chemistry

2 answers:

netineya [11]3 years ago

7 0

The gas flows from higher concentration/pressure to lower concentration/pressure, which is outside the ball.

andreev551 [17]3 years ago

7 0

The gas partices lose the amount of concentration of the particles because they spread qpart and move faster.

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How many grams in 4.53 moles of MgBr2

musickatia [10]

Answer:

520.12554

Explanation:

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2 years ago

Answer truthfully:))

BartSMP [9]

Answer:

b) velocity.

c) velocity, m/s²

d)change in velocity, change in direction, change in both velocity and direction.

e) increasing or decreasing

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2 years ago

A metal sample weighing 129.00 grams and at a temperature of 97.8 degrees Celsius was placed in 45.00 grams of water in a calori

Nitella [24]

Answer : The specific heat of metal is $0.481J/g^oC$ .

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_1$ = mass of metal = 129.00 g

$m_2$ = mass of water = 45.00 g

$T_f$ = final temperature = $39.6^oC$

$T_1$ = initial temperature of metal = $97.8^oC$

$T_2$ = initial temperature of water = $20.4^oC$

Now put all the given values in the above formula, we get

$129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC$

$c_1=0.481J/g^oC$

Therefore, the specific heat of metal is $0.481J/g^oC$ .

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3 years ago

What is the name of B2(SeO4)3

Gnoma [55]

This compound is Boron selenate. Molar mass of B2(SeO4)3 is 450.4948 g/mol.

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3 years ago

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A _____ is a classification of an element based on its current status, position, or use in a document.

lina2011 [118]

Pseudo-class is the answer

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3 years ago