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lisov135 [29]
1 year ago
14

Allicin is the compound responsible for the characteristic smell of garlic. An analysis of the compound gives the following perc

ent composition by mass: c: 44. 4 percent; h: 6. 21 percent; s: 39. 5 percent; o: 9. 86 percent. Calculate its empirical formula. What is its molecular formula given that its molar mass is about 162 g?.
Chemistry
1 answer:
saveliy_v [14]1 year ago
6 0

The molecular formula of the Allicin is, C₁₈H₃₀S₆O₃ and the empirical formula is C₆H₁₀S₂O

the molecular formula can be calculated as follows:

If a percentage is provided, we will assume that the entire mass is 100 grams.

As a result, each element's mass is equal to the percentage indicated.

C weighs 44.4 g.

H weighs 6.21 g.

S weighs 39.5 g.

O's mass is 9.86 g.

C has a molar mass of 12 g/mole.

H has a molar mass of 1 g/mole.

S has a molar mass of 32 g/mole.

O has a molar mass of 16 g/mole.

first, convert given masses into moles.

Moles of C =<u>      mass C       </u>= <u>    44.4 g    </u>  = 3.7 moles

                    molar mass C       12 g/mole.

Moles of H = <u>      mass H       </u>= <u>    6.21 g</u>.<u>    </u>  = 6.21 moles

                      molar mass           1 g/mole.

Moles of S = <u>      mass S       </u>= <u>    39.5 g.    </u>  = 1.23 moles

                      molar mass          32 g/mole.

Moles of O =  <u>      mass O       </u>= <u>    9.86 g.    </u>  = 0.62 moles

                      molar mass          16 g/mole.

then we find the mole ratio by divide each value of moles by the smallest number of moles calculated.

For C =<u> 3.7 moles</u> = 5.96 ≈ 6

           0.62 moles

For H = <u> 6.21  moles</u> = 10.01≈ 10

           0.62 moles

For S = <u> 1.23 moles</u> = 1.98 ≈ 2

           0.62 moles

For O = <u> 0.62 moles</u> = 1

             0.62 moles

The ratio of C : H : S : O = 6 : 10 : 2 : 1

The Empirical formula is C₆H₁₀S₂O

The empirical formula weight = 6(12) + 10(1) + 2(32) + 1(16) = 162 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n= <u>molecular formula </u>= <u>486</u> =3

    empirical formula     162

Molecular formula = (C₆H₁₀S₂O)₃ =C₁₈H₃₀S₆O₃

Therefore, the molecular of the compound is, C₁₈H₃₀S₆O₃

learn more about molecular formula here: brainly.com/question/16904381

#SPJ4

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First convert grams to moles using molar mass of butane that is 58.1 g

3.50g C4H10 x (1 mol C4H10)/(58.1g C4H10) = 0.06024 mol C4H10 <span>

<span>Now convert moles to molecules by using Avogadro’s number

0.06024 mol C4H10 x (6.022x10^23 molecules C4H10)/(1 mol C4H10) = 3.627x10^22 molecules C4H10 

And there are 4 carbon atoms in 1 molecule of butane, so use the following ratio: 

3.627 x 10^22 molecules C4H10 x (4 atoms C)/(1 molecule C4H10) 
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How many grams of P4O10 would be produced when 0.700 mole of phosphorus is burned?
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We can solve the equation and show the solution below:

Oxygen atomic number is 16.
Phosphorus atomic number is 32.

We have the molecular weight:
Molecular weight = (31*4) + (16*10)
Molecular weight = 284 grams/mol

Solving for the grams:

0.4 mole (for P4) * (1 mol P4O10/1 mol P4) * (284 grams P4O10/1 mole P4O10)
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The answer is 113.6 grams.
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The rate law for the decomposition of phosphine (PH3) is below. It takes 120. s for 1.00 M PH3 to decrease to 0.250 M. How much
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Answer: 588.8 seconds

Explanation:

1.00 - 0.25 = 0.75M

4.00 - 0.320 = 3.68M

Therefore,

0.75M in 120 seconds

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Cross multiply:

0.75*x = 120*3.68

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The question is incomplete, complete question is :

In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?

Structure is given in an image?

Answer:

There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.

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Total numbers of carbon = 10

Number of primary carbons that is carbon joined to just single carbon atom = 6

Number of secondary carbons that is carbon joined to two carbon atoms = 1

Number of tertiary carbons that is carbon joined to three carbon atoms = 2

Number of quartenary carbons that is carbon joined to four carbon atoms = 1

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