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lisov135 [29]
1 year ago
14

Allicin is the compound responsible for the characteristic smell of garlic. An analysis of the compound gives the following perc

ent composition by mass: c: 44. 4 percent; h: 6. 21 percent; s: 39. 5 percent; o: 9. 86 percent. Calculate its empirical formula. What is its molecular formula given that its molar mass is about 162 g?.
Chemistry
1 answer:
saveliy_v [14]1 year ago
6 0

The molecular formula of the Allicin is, C₁₈H₃₀S₆O₃ and the empirical formula is C₆H₁₀S₂O

the molecular formula can be calculated as follows:

If a percentage is provided, we will assume that the entire mass is 100 grams.

As a result, each element's mass is equal to the percentage indicated.

C weighs 44.4 g.

H weighs 6.21 g.

S weighs 39.5 g.

O's mass is 9.86 g.

C has a molar mass of 12 g/mole.

H has a molar mass of 1 g/mole.

S has a molar mass of 32 g/mole.

O has a molar mass of 16 g/mole.

first, convert given masses into moles.

Moles of C =<u>      mass C       </u>= <u>    44.4 g    </u>  = 3.7 moles

                    molar mass C       12 g/mole.

Moles of H = <u>      mass H       </u>= <u>    6.21 g</u>.<u>    </u>  = 6.21 moles

                      molar mass           1 g/mole.

Moles of S = <u>      mass S       </u>= <u>    39.5 g.    </u>  = 1.23 moles

                      molar mass          32 g/mole.

Moles of O =  <u>      mass O       </u>= <u>    9.86 g.    </u>  = 0.62 moles

                      molar mass          16 g/mole.

then we find the mole ratio by divide each value of moles by the smallest number of moles calculated.

For C =<u> 3.7 moles</u> = 5.96 ≈ 6

           0.62 moles

For H = <u> 6.21  moles</u> = 10.01≈ 10

           0.62 moles

For S = <u> 1.23 moles</u> = 1.98 ≈ 2

           0.62 moles

For O = <u> 0.62 moles</u> = 1

             0.62 moles

The ratio of C : H : S : O = 6 : 10 : 2 : 1

The Empirical formula is C₆H₁₀S₂O

The empirical formula weight = 6(12) + 10(1) + 2(32) + 1(16) = 162 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n= <u>molecular formula </u>= <u>486</u> =3

    empirical formula     162

Molecular formula = (C₆H₁₀S₂O)₃ =C₁₈H₃₀S₆O₃

Therefore, the molecular of the compound is, C₁₈H₃₀S₆O₃

learn more about molecular formula here: brainly.com/question/16904381

#SPJ4

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