The molecular formula of the Allicin is, C₁₈H₃₀S₆O₃ and the empirical formula is C₆H₁₀S₂O
the molecular formula can be calculated as follows:
If a percentage is provided, we will assume that the entire mass is 100 grams.
As a result, each element's mass is equal to the percentage indicated.
C weighs 44.4 g.
H weighs 6.21 g.
S weighs 39.5 g.
O's mass is 9.86 g.
C has a molar mass of 12 g/mole.
H has a molar mass of 1 g/mole.
S has a molar mass of 32 g/mole.
O has a molar mass of 16 g/mole.
first, convert given masses into moles.
Moles of C =<u> mass C </u>= <u> 44.4 g </u> = 3.7 moles
molar mass C 12 g/mole.
Moles of H = <u> mass H </u>= <u> 6.21 g</u>.<u> </u> = 6.21 moles
molar mass 1 g/mole.
Moles of S = <u> mass S </u>= <u> 39.5 g. </u> = 1.23 moles
molar mass 32 g/mole.
Moles of O = <u> mass O </u>= <u> 9.86 g. </u> = 0.62 moles
molar mass 16 g/mole.
then we find the mole ratio by divide each value of moles by the smallest number of moles calculated.
For C =<u> 3.7 moles</u> = 5.96 ≈ 6
0.62 moles
For H = <u> 6.21 moles</u> = 10.01≈ 10
0.62 moles
For S = <u> 1.23 moles</u> = 1.98 ≈ 2
0.62 moles
For O = <u> 0.62 moles</u> = 1
0.62 moles
The ratio of C : H : S : O = 6 : 10 : 2 : 1
The Empirical formula is C₆H₁₀S₂O
The empirical formula weight = 6(12) + 10(1) + 2(32) + 1(16) = 162 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
n= <u>molecular formula </u>= <u>486</u> =3
empirical formula 162
Molecular formula = (C₆H₁₀S₂O)₃ =C₁₈H₃₀S₆O₃
Therefore, the molecular of the compound is, C₁₈H₃₀S₆O₃
learn more about molecular formula here: brainly.com/question/16904381
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