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babymother [125]
3 years ago
15

Calculate the volume of a tin block that has a mass of 95.04 grams at stp

Chemistry
2 answers:
stiks02 [169]3 years ago
8 0

Answer : The volume of tin block is, 13.0 mL

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

Density=\frac{Mass}{Volume}

Given :

Mass of tin = 95.04 grams

Density of tin at STP = 7.287 g/mL

Now put all the given values in the above formula, we get the volume of tin block.

7.287g/mL=\frac{95.04g}{Volume}

Volume=\frac{95.04g}{7.287g/mL}=13.0mL

Therefore, the volume of tin is 13.0 mL

sergejj [24]3 years ago
3 0
Thank you for posting your question here. I am just assuming to that the density of tin is <span>7.31 g/cm^3, you can change it it is not the number. Below is the solution. I hope it helps. 

</span><span>95.04g x (1 cm³ / 7.31g) = 13.0 cm³</span>
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Answer:

Mass =  42.8g

Explanation:

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Observe that every 4 mole of ammonia requires 5 moles of oxygen to obtain 4 moles of Nitrogen oxide and 6 moles of water.

Step 1: Determine the balanced chemical equation for the chemical reaction.

The balanced chemical equation is already given.

Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).

Ammonia = 63.4g × 1mol / 17.031 g = 3.7226mol

Oxygen = 63.4g × 1mol / 32g = 1.9813mol

Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.

If all of the 1.9831 moles of oxygen were to be used up, there would need to be 1.9831 × 4 / 5 or 1.5865 moles of Ammonia. We have 3.72226 moles of ammonia - Far excess. Because there is an excess of Ammonia, the Oxygen amount is used to calculate the amount of the products in the reaction.

Step 4: Use the amount of limiting reactant to calculate the amount of H2O produced.

5 moles of O2  = 6 moles of H2O

1.9831 moles = x

x = (1.9831 * 6 ) / 5

x = 2.37972 moles

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6 0
3 years ago
Can someone help me with #35,37,39,41 please
adoni [48]
35 b.
37 h
39 i
41 d
hope that helps
4 0
3 years ago
What is the cell potential of an electrochemical cell that has the half-reactions shown below?
Karo-lina-s [1.5K]

Answer:

E°(Ag⁺/Fe°) = 0.836 volt

Explanation:

3Ag⁺ + 3e⁻ => Ag°;            E° = +0.800 volt

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_________________________________

Fe°(s) + 3Ag⁺(aq) => Fe⁺³(aq) + 3Ag°(s) ...    

E°(Ag⁺/Fe°) = E°(Ag⁺) - E°(Fe°) = 0.800v - ( -0.036v) = 0.836 volt

4 0
2 years ago
If 10.0 grams of NaHCO3 is added to 10.0 g of HCl, determine the efficiency of baking soda as an antacid if 6.73 g of NaCl was p
Lapatulllka [165]

Answer:

percentage yield of NaCl = 96.64%

Explanation:

The reaction was between NaHCO3 and HCl .The chemical equation can be represented below:

NaHCO3 + HCl → NaCl + H2O + CO2 . The balance equation is

NaHCO3 + HCl → NaCl + H2O + CO2

The question ask us to calculate the percentage yield of NaCl.

The efficiency of NaHCO3 as an antacid , the limiting reactant is NaHCO3

as

1 mole of NaHCO3 produces 1 mole of NaCl

Therefore,

molar mass of NaHCO3 = 23 +1 + 12 + 48 = 84 g

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since 84 g of NaHCO3 produces 58.5 g of NaCl

10 g of NaHCO3 will produce ? grams of NaCl

cross multiply

Theoretical yield of NaCl = (10 × 58.5)/84

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percentage yield of NaCl = 6.73/6.9642857143 × 100

percentage yield of NaCl = 673/6.9642857143

percentage yield of NaCl = 96.635897436%

percentage yield of NaCl = 96.64%

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