Hello there.
<span>6. The specific heat capacity of aluminum is 0.22 cal/g°C. How much energy needs to flow into 20.0 grams of aluminum to change its temperature by 15°C?
</span><span>1363 cal
</span>
Answer:
0.025V + (0.000218V/s³) t³
Explanation:
Parameters given:
Radius of coil, r = 3.85 cm = 0.0385 m
Number of turns, N = 450
Magnetic field, B = ( 1.20×10^(−2) T/s )t + (2.60×10^(−5) T/s4 )t^4.
The magnitude of Induced EMF is given as:
E = N * A * dB/dt
Where A is the area of the coil
First, we differentiate the magnetic field with respect to time:
dB/dt = 0.012 + 0.000104t³
Therefore, EMF will be:
E = 450 * 3.142 * (0.012 + 0.000104t³)
E = 2.096(0.012 + 0.000104t³)
E = 0.025V + (0.000218V/s³)t³
Answer:
A
Explanation:
When you pull the string the weight will experience a downward force and come closer to the vertical tube. And the angle between weight and hand through string is decreased so the angular velocity decreases
Divide 2500 g by 500 cc. The quotient is 5 g/cc ... the density.
Answer:
Explanation:
= Heat capacity of Hg = 28 J/mol
= Change in temperature = 
= Enthalpy of fusion = 2.29 kJ/mol
The number of moles is given by
Heat is given by
Heat released is given by
Total heat is given by
The total heat released is
