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2 years ago

Which of the following best explains why electromagnetic waves of all wavelengths have the same speed in a vacuum?

1 answer:

8 0

All electromagnetic waves have the same manner of propagation; alternating electric and magnetic fields that's why electromagnetic waves of all wavelengths have the same speed in a vacuum

An altering magnetic field will cause an altering electric field and vice versa. Electromagnetic waves are created from these shifting fields. In contrast to mechanical waves, electromagnetic waves can travel without a medium. The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves or EM waves.

In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves. Almost the majority of the energy that sustains life on our planet comes from electromagnetic waves that flow from the sun to Earth through space. Technology is a necessity for many additional electromagnetic wave sources. Examples include X-rays, radio waves, and microwaves.

To learn more about electromagnetic waves please visit -
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What is an example of applying the law of conservation of mass?

Slav-nsk [51]

For example, a bonfire/campfire and a burning candle

4 0

3 years ago

395,000 meters in 9000

marta [7]

Answer:

43.88 meters per second

Explanation:

The computation of the speed is shown below:

As we know that

$Speed = \frac{Distance}{time}$

where,

Distance is 395,000 meters

Time is 9,000 seconds

Now placing these values to the formula

So, the speed is

$= \frac{395,000}{9,000}$

= 43.88 meters per second

As speed shows the relation between the distance and time and the same is to be considered i.e by applying the formula

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4 years ago

A Celcius and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermo

Sholpan [36]

Answer:

(d) 22.22 °C

Explanation:

Because in 1 Celcius is 1.8 fahrenheit apart from 2 celcius, so

when °C is 0 f is 32, when °C is 1 = 33.8 , so it rises with quantities of 1.8 fahrenheit

7 0

3 years ago

A box of negligible mass rests at the left end of a 2.00-m, 25.0-kg plank (Fig. P11.43). The width of the box is 75.0 cm, and sa

Sati [7]

Answer:

Required mass of sand is 20 kg

Explanation:

Given:

Mass of the plank = 25 kg

Distance of the Center of gravity of the Plank from the fulcrum = $\frac{2}{2}-0.50 = 0.5m$

Distance of the Center of gravity of the sand box from the fulcrum = $\frac{2}{2}-\frac{0.75}{2}= 0.625m$

Balancing the torque due to the plank and the sand box with respect to the fulcrum

Torque = Force × perpendicular distance

thus, we get

(25 × g) × 0.5 = weight of sand × 0.625

where, g is the acceleration due to gravity

(25 × g) × 0.5 = (mass of sand × g) × 0.625

mass of sand = 20 kg

<u>Hence, the required mass of the sand is </u><u>20 kg</u>

8 0

3 years ago

A 0.20 kg mass attached to the end of a spring causes it to stretch 3.0 cm. What is the spring constant? What is the potential e

SVEN [57.7K]

Given that the mass is m = 0.2 kg and the displacement is x = 3 cm = 0.03 m

We have to find the spring constant and potential energy.

The spring constant can be calculated by the formula

$\begin{gathered} F=\text{ kx} \\ mg\text{ = kx} \\ k\text{ = }\frac{mg}{x} \end{gathered}$

Here, k is the spring constant.

g = 9.8 m/s^2 is the acceleration due to gravity.

Substituting the values, the spring constant will be

$\begin{gathered} k=\frac{0.2\times9.8}{0.03} \\ =\text{ 65.33 N/m } \end{gathered}$

The potential energy can be calculated as

$\begin{gathered} U=\frac{1}{2}kx^2 \\ =\frac{1}{2}\times65.33\text{ }\times(0.03)^2 \\ =\text{ 0.0293 J} \end{gathered}$

8 0

1 year ago