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lesantik [10]
3 years ago
10

EMERGENCY HELP ME OUT

Chemistry
1 answer:
lesya [120]3 years ago
7 0

Answer:

D, The volume will be multiplied by a factor of 4

Explanation:

First find the height

V = π(r^2)h

Plug in what we know

83 = π(3^2)h

83 = π(9)h

83  = (9π)h

9\pi = 28.27

83/28.27 = (28.27)h/28.27

h = 2.94

Then find the volume of the new can by doubling the radius

3 x 2 = 6

r = 6

V = π(r^2)h

V = π(6^2)2.94

V = π(105.84)

V =332.51

For the first one, they rounded to the nearest whole #, so let's do the same.

V = 333

Then divide 333 by 83 to get 4

Therefore, the volume will be multiplied by a factor of 4

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A sample of nitrogen containing 3.0×10^23 molecules has the same number of molecules as a sample containing
Daniel [21]

Answer:

D) 0.50 mole of Ne

Explanation:

Given data:

Number of molecules of nitrogen = 3.0×10²³ molecules

Which sample contain same number of molecules as nitrogen= ?

Solution:

A) 0.25 mole of O₂

1 mole = 6.022×10²³ molecules

0.25 mol × 6.022×10²³ molecules / 1 mol

1.51×10²³ molecules

B) 2.0 moles of He.

1 mole = 6.022×10²³ molecules

2.0 mol × 6.022×10²³ molecules / 1 mol

12.044×10²³ molecules

C) 1.0 moles of H₂

1 mole = 6.022×10²³ molecules

D) 0.50 mole of Ne

1 mole = 6.022×10²³ molecules

0.50 mol × 6.022×10²³ molecules / 1 mol

3.0×10²³ molecules

5 0
3 years ago
4 Na + O2 → 2 Na2O<br><br> 6.79 moles of O2 will react to form how many moles of Na2O?
Nataly_w [17]

Answer:

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Explanation:

The balanced reaction expression is given as:

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Given parameters:

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Unknown:

Number of moles of Na₂O

Solution:

 To solve this problem;

            1 mole of O₂  will produce 2 moles of Na₂O ;

            6.97 moles of O₂ will produce 6.97 x 2  = 13.94moles of Na₂O

6 0
3 years ago
How many grams of water can be produced when 65.5 grams of sodium hydroxide reacts with excess sulfuric acid? Unbalanced equatio
kap26 [50]
The balanced reaction that describes the reaction between sulfuric and sodium hydroxide to produce sodium sulfate and water is expressed <span>H2SO4 + 2NaOH → 2H2O + Na2SO4. When 65.5 grams of sodium hydroxide reacts with excess sulfur, we need first to convert the mass to moles and multiply by stoich ratio 2/2 or 1. Hence the moles is multiplied to the molar mass of water. The final answer is 29.475 grams water.</span>
8 0
4 years ago
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irinina [24]

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You're welcome :)

5 0
3 years ago
How many moles of oxygen are required to produce 37.15 g CO2?
n200080 [17]
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6 0
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