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Ket [755]
3 years ago
10

which of the following statements about planetary motion is false? a. each planet would move in a straight line without the sun'

s gravitational pull. b. each planet moves in a circular orbit around the sun. c. a planet's speed changes as it orbits the sun. d. each planet has a period of revolution and a period of rotation.
Chemistry
2 answers:
Vika [28.1K]3 years ago
7 0
Given the options it would be B.

Planets orbit the sun in a elliptical pattern around the sun, rather than in a circle.

Hope this helps!
vlabodo [156]3 years ago
5 0

Answer:

B.

Explanation:

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In an experiment, a student needs 250.0 mL of a 0.100 M copper (II) chloride solution. A stock solution of 2.00 M copper (II) ch
LekaFEV [45]

Answer : The volume of stock solution needed are, 12.5 mL

Explanation :

Formula used :

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the initial molarity and volume of copper (II) chloride.

M_2\text{ and }V_2 are the final molarity and volume of stock solution of copper (II) chloride.

We are given:

M_1=0.100M\\V_1=250.0mL\\M_2=2.00M\\V_2=?

Putting values in above equation, we get:

0.100M\times 250.0mL=2.00M\times V_2\\\\V_2=12.5mL

Hence, the volume of stock solution needed are, 12.5 mL

8 0
3 years ago
Pls help me !!!! Is for chemistry
Sphinxa [80]

Answer:

Explanation:

1) Molarity of the solution is (0.50/0.75)x1 = 0.66666 Mol/L

2) Molar mass of NaCl is 23+35 = 58g

Molarity = (0.5/58)/0.075 = 0.115 Mol/L

3) Molar mass of Li_{2}SO_{4} = 7x2 + 32 + 16x2 = 78g

Molarity = (734/78)/0.875 = 10.754 Mol/L

5) Molar mass of   Pb(C_{2}H_{3}O_{2})_{4}

= 207.2 + ((12x2) + (1x3) + (16x2))x4

= 207.2 + (24+3+32)x4 = 443.2g

Molarity = (0.0672/443.2)/0.1335 = 0.001135 Mol/L

6) Both are the same.

Solution 1 Molarity = 1.0/1.0 = 1 Mol/L

Solution 2 Molarity = 1.0/1.0 = 1 Mol/L

Molarities of the solutions are the same.

7 0
3 years ago
Identify the group of elements that corresponds to each of the following generalized electron configurations and indicate the nu
Alja [10]

Answer:

(a) [Noble gas] ns² np⁵: Number of unpaired electron is 1 and belongs to group 17 i.e. halogen group of the periodic table.

(b) [noble gas] ns² (n-1)d²: Number of unpaired electron is 2 and belongs to group 4 of the periodic table.

(c) [noble gas] ns² (n-1)d¹⁰ np¹: Number of unpaired electron is 1 and belongs to group 13 of the periodic table.

(d)[noble gas] ns² (n-2)f⁶ : Number of unpaired electron is 6 and belongs to group 8 of the periodic table.

Explanation:

In the Periodic table, the chemical elements are arranged in 7 rows, called periods and 18 columns, called groups. They are organized in increasing order of atomic numbers.

(a) [Noble gas] ns² np⁵

As the total number of electrons in the p-orbital is 5. Therefore, the number of unpaired electron is 1.

This element has 2 electrons in ns orbital and 5 electrons in np orbital. <u>So there are 7 valence electrons.</u>

Therefore, this element belongs to the group 17 i.e. halogen group of the periodic table.

(b) [noble gas] ns² (n-1)d²

As the total number of electrons in the d-orbital is 2. Therefore, the number of unpaired electrons is 2.

This element has 2 electrons in ns orbital and 2 electrons in (n-1)d orbital. So there are <u>4 valence electrons.</u>

Therefore, this element belongs to the group 4 of the periodic table.

(c) [noble gas] ns² (n-1)d¹⁰ np¹

As the total number of electrons in the p-orbital is 1. Therefore, the number of unpaired electron is 1.

This element has 2 electrons in ns orbital and 1 electron in np orbital. So there are <u>3 valence electrons</u>.

Therefore, this element belongs to the group 13 of the periodic table.

(d)[noble gas] ns² (n-2)f⁶

As the total number of electrons in the f-orbital is 6. Therefore, the number of unpaired electron is 6.

This element has 2 electrons in ns orbital and 6 electrons in (n-2)f orbital. So there are <u>8 valence electrons.</u>

Therefore, this element belongs to the group 8 of the periodic table.

3 0
3 years ago
Carbon 14 is an example of blank dating
Brilliant_brown [7]

Answer:

Carbon

Explanation:

It's in the name lol

6 0
3 years ago
Can you help me on this question
Luba_88 [7]

the answer is a !!

I hope this helps

Issa gg

3 0
3 years ago
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