Which pair of vectors is orthogonal?

Answer:

3(x)-3(9)

Step-by-step explanation:

The brackets means you times everything within the brackets with everything outside it. So it would be 3 times x take away 3 times 9

8 0

2 years ago

Three points, A, B, and C exists in space such that B is "between" A and C. It is known that AB=7, BC=4, and AC=9. Are points A,

EleoNora [17]

If the points are collinear, then that would mean that the points lie on the same line when joined to each other. In order to confirm this, the distances between the points must sum up to the length of the line.

AB + BC = AC
7 + 4 ? 9
11 ≠ 9

Since they do not sum up, therefore, the points are not collinear.

8 0

2 years ago

Out of 25 attempts, a basketball player scored 17 times. One- half of the missed shots are what percent of the total shots

Alona [7]

16% 25-17=8 8/2=4 4/25=16/100

8 0

3 years ago

A recipe submitted to a magazine by one of its subscribers’ states that the mean baking time for a cheesecake is 55 minutes. A t

EastWind [94]

Answer:

$t=\frac{59.4-55}{\frac{3.239}{\sqrt{10}}}=4.296$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =P(t_{(9)}>4.296)=0.001$

And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55.

Step-by-step explanation:

Information given

We have the following data: 54 55 58 59 59 60 61 61 62 65

The sample mean and deviation can be calculated with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X-i -\bar x)^2}{n-1}}$

$\bar X=59.4$ represent the sample mean

$s=3.239$ represent the sample standard deviation

$n=10$ sample size

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to test if the true mean is higher than 55, the system of hypothesis would be:

Null hypothesis: $\mu \leq 55$

Alternative hypothesis: $\mu > 55$

Replacing the info given we got:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing the info given we got:

$t=\frac{59.4-55}{\frac{3.239}{\sqrt{10}}}=4.296$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =P(t_{(9)}>4.296)=0.001$

And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55

8 0

3 years ago

Answer the question below, topic: scaled topies

katen-ka-za [31]

Answer:

The answer is C

Step-by-step explanation:

So, in A, the ratio is 5:3- understand? And in C, the ratio is 10:6. You multiply 5(2) and 3(2), and you get 10:6

-Hope this helped!

3 0

3 years ago