Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
Answer:
<h3>
y = 20</h3><h3 />
Step-by-step explanation:
line RPN = 180 = 4y - 10 + 90 + y
180 - 90 + 10= 5y
100 = 5y
y = 100/5
y = 20
Answer: 3 4/5
Explanation: 19 divided by 5 is 3 4/5
First you want to change the fractions to the same denominator
3/4 = 9/12 and 2/3 = 8/12
then you put it in ratio form...
the answer is 9:8
Answer:
18+3b-2b-1
b+17
Step-by-step explanation:
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