Need help ASAP!!!!!!!!!!!

Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

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4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago

Kim and Jay leave at the same time to travel 25 miles to the beach.Kim drives 9 miles in 12 minutes.Jay drives 10 miles in 15 mi

kow [346]

Jay will arrive before kim

4 0

3 years ago

Read 2 more answers

A poster is to have a total area of 125 cm2. There is a margin round the edges of 6 cm at the top and 4 cm at the sides and bott

jeka57 [31]

Answer:

The correct answer is 15 cm.

Step-by-step explanation:

Let the width of the required poster be a cm.

We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.

Similarly total margin combining both the sides is (4+4=) 8 cm.

So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } $cm^{2}$

This area is equal to 125 $cm^{2}$ as per as the given problem.

∴ (a - 10) × (a - 8) = 125

⇒ $a^{2}$ - 18 a +80 -125 =0

⇒ $a^{2}$ - 18 a -45 = 0

⇒ (a-15) (a-3) = 0

By law of trichotomy the possible values of a are 15 and 3.

But a=3 is absurd as a $>$ 4.

Thus the required answer is 15 cm.

7 0

3 years ago

Read 2 more answers

If it continues to snow at the same rate, how many inches of snow would you expect after 6.5 hours? If you get stuck, you can us

ANTONII [103]

Answer:

hshshshshshshdudjhshwbebbsh

676494664jjxjduskqmwkwk

keieiebehidus

63434649496

jjdjsisi3343494966jssisusjsjs

Step-by-step explanation:

shhshshshshsisuwhsjsjjdjdjdososnhwjsjsjd

sjsjdjdjdjdjjdjdjdjdjdjdjdjdjdjdj

mdkdjdjdjdjdjjdjdjdjdj

djjdjdjdjd

d

djdjdjueiejehegdhdhdjjd

dsuduududhehh34346646464644

466464643

5 0

3 years ago

Read 2 more answers

Help______________________________________

ser-zykov [4K]

The right step followed in the system to get he equations is (D). To get the system B. The second equation in system A was replaced by the sum of that equation and the first equation multiplied by 6. The solution to system B will be the same as the solution of system A.

<h3>Meaning of Simultaneous Equation.</h3>

A simultaneous equation can be defined as an equation that possesses two unknowns and one constant.

The solution to the problem can only be gotten by solving it side by side with another equation of the same format.

In conclusion, The right step followed in the system to get he equations is (D). To get the system B. The second equation in system A was replaced by the sum of that equation and the first equation multiplied by 6. The solution to system B will be the same as the solution of system A.

Learn more about simultaneous equation: brainly.com/question/148035

#SPJ1

3 0

2 years ago