Answer:
a) e-0.03x(0.3-0.009x)
b) 33 hrs 20 min
c) 17.182
Step-by-step explanation:
Taking derivative of the above equation would give us the rate for change in donations :
hence
f'(x) = d/dx (0.3xe-0.03x)
using product rule of derivation where (uv)' = u'v +v'u
hence
f'(x) = (e-0.03x)d/dx(0.3x) + 0.3x*d/dx(e-0.03x)
= 0.3e-0.03x + 0.3x(-0.03)(e-0.03x)
f'(x) =0.3e-0.03x -0.009xe-0.03x
hence
a) rate of change in donations = e-0.03x(0.3-0.009x) taking exponent common
b) f'(x) = 0 according to statement
hence 0 = e-0.03x(0.3-0.009x)
0 = 0.3 - 0.009 x
which gives x = 33.33 hrs i.e after 33 hrs and 20 minutes rate of change of donations is 0.
c) donation level at the time is given by
f(x) = 0.3xe-0.03x
f(33.33) = 0.3 (33.33)e-0.03(33.33)
= 17.182
That is 17.182 thousand donations were made at that time.
Answer:1. = 4x+8
2. 2a²-a+1
Step-by-step explanation:
1. ((x+2)+3x+6. 2. 2a(a-1)-a+1
((x+2)+3x+6
= x+2+3x+6
= 4x+8
2a(a-1)-a+1
2a²-2a-a+1
2a²-a+1
Answer:
Plug in the value to the equation to see which set works.
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
