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zlopas [31]
3 years ago
10

Gil charges $5 per bracelet plus $2 for each string colour. If Gil makes 3 bracelets

Mathematics
2 answers:
hichkok12 [17]3 years ago
8 0

Answer: 15 + 2x

Step-by-step explanation:

5b + 2x

5 (3) + 2x

15 + 2x

I think I'm right so I hope it helped!!

Natali5045456 [20]3 years ago
3 0
Expression for this word problem: $5x + 2.
Now, if Gil makes three bracelets, then we will apply and substitute this into our equation:
$5(3) + 2 = $17.00
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o-na [289]
It might be the first box, because i had that same question on my hw this year, lol what a coincidence
7 0
3 years ago
Read 2 more answers
Tony operates a skate rental company. He charges an equipment fee of $3 plus $6 per hour. Which equation represents this linear
slava [35]

Answer: A) y = 6x +3

Step-by-step explanation:

Let x represent the number of hours. $6 per hour can now be written as 6x.

Now, we must account for the $3 flat, fee and add it to 6x, getting 6x + 3

6 0
3 years ago
Show that the equation x^3+7x-4=0 has a solution between x=0 and x=1
Aleksandr [31]

Step-by-step explanation:

Using the Intermediate Value Theorem, the following is applied:

"If f(x) is a continuous on interval [a,b] and we have two points f(a) and f(b) then there must be some value c such that f(a)<f(c)<f(b).

So here there must be a c such that

f(0) < f(c) < f(1)

Note: F(c)=0, the questions that the function have a solution between 0 and 1, so that means we must have some value, c such that f(c)=0 that exists

Next, plug in the x values into the function

f(0)  =  - 4

f(1) =  {1}^{3}  + 7(1) - 4 = 4

Since cubic functions are continuous and -4<0<4, then there is a solution c that lies between f(0) and f(1)

3 0
2 years ago
How many different groups of three kids can you make from seven kids?
katovenus [111]
This is combination problem since the order or arrangement matters. This is easily solvable with your scientific calculator. The formula would be nCr, where n is the total number of persons, and r is the number of persons in a group. So, using your calculator,

7C3 = 35

There can be 35 different groups.
3 0
3 years ago
Solve (3x+8)(y^2+4) dx +4
Anna35 [415]

It's been four years since I last did a problem of this particular nature. :)


Try this: divide both sides of the given equation by (x^2-5x+6), obtaining


(3x+8)(y^2+4)          + 4y(x^2+5x+6) dy

-------------------- dx + ------------------------- dy = 0

x^2+5x + 6                         x^2+5x + 6


This gives us:


(3x+8)(y^2+4)

-------------------- dx + 4ydy = 0

(x+2)(x+3)


Now divide all 3 terms by y^2+4:


3x+8

--------------- dx + 4ydy = 0 This completes the separation of variables.

(x+2)(x+3)


Now we'll need to integrate each of the 3 terms.


3x+8

--------------- dx + 4ydy = 0 can be re-written in the form

(x+2)(x+3)


3x     +8              A           B

--------------- = --------- + ---------- We will need to determine the values

(x+2)(x+3)        x+2       x+3 of A and B (partial fraction expansion).


I trust you know how to do this; if not, let me know and I'll help you with that also.


I obtained B=2 and A = 1. You might want to verify that 1/(x+2) + 2/(x+3) =


3x+8

-------------- .

(x+2)(x+3)


Integrating the left side of this d. e. results in ln(x+2) + ln(x+3).

Integrating 4ydy results in 4*y^2/2, or 2y^2.


Integrating 0 results in a constant, C.


Thus,


ln(x+2) + ln(x+3) + 2y^2 = C is the solution of this d. e.


7 0
3 years ago
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