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Zielflug [23.3K]
3 years ago
5

What is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radiu

s r1 = 0.775 m ?
Physics
1 answer:
alexira [117]3 years ago
7 0
The expression for the flux through a sphere is
flux = charge/Enot (i.e. epsillon not: a constant)

this shows that flux doesn't vary with radius but with the charge of the points
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What's true about the elliptical path that the planets follow around the sun?
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1 year ago
An infinite sheet of charge, oriented perpendicular to the x-axis, passes through x = 0. It has a surface charge density σ1 = -2
pishuonlain [190]

Answer:

E_{total}=4.82*10^6N/C

vector with direction equal to the axis X.

Explanation:

We use the Gauss Law and the superposition law in order to solve this problem.

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E=\sigma/(2\epsilon_o)

Then:

E_{total}=(\sigma_1+\sigma_2)/(2\epsilon_o)=(-2.7*10^{-6}+88*10^{-6})/(2*8.85*10^{-12})=4.82*10^6N/C

This electric field has a direction in the axis perpendicular to the sheets, that means it has the same direction as the axis X.

7 0
3 years ago
Read 2 more answers
A thin layer of liquid methylene iodide (n = 1.756) is sandwiched between two flat, parallel plates of glass (n = 1.50). What mu
Harrizon [31]

Answer:

t = 96.1 nm

Explanation:

For strong reflection through liquid layer we know that the path difference between two reflected light rays must be integral multiple of wavelength

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\mu = 1.756

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\lambda = 675 nm

now we have

2(1.756) t = \frac{675 nm}{2}

t = 96.1 nm

5 0
3 years ago
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