1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry [639]
2 years ago
10

Function f(x)=|x| is transformed to create function g(x)=|x+4|+3. What transformations are performed to function f to get functi

on g? Select each correct answer.
Function f is translated 4 units to the right.

Function f is translated 3 units to the left.

Function f is translated 4 units down.

Function f is translated 3 units up.

Function f is translated 4 units up.

Function f is translated 4 units to the left.

Function f is translated 3 units to the right.

Function f is translated 3 units down.
Mathematics
1 answer:
Ahat [919]2 years ago
3 0

Answer:

Step-by-step explanation:

Function f(x)=|x| is transformed to create function g(x)=|x+4|+3. What transformations are performed to function f to get function g? Select each correct answer.

Function f is translated 4 units to the right.

Function f is translated 3 units to the left.

Function f is translated 4 units down.

(this one is correct) Function f is translated 3 units up.

Function f is translated 4 units up.

(this one is correct) Function f is translated 4 units to the left.

Function f is translated 3 units to the right.

Function f is translated 3 units down.

You might be interested in
The graph shows amounts of water and flour that can be used to make dough. Make a ratio table that represents a different ratio
Oksanka [162]

Answer:

sorry i need more points

Step-by-step explanation:

hi hi hi hi

5 0
2 years ago
Read 2 more answers
A machine can stamip 36 bottle caps in ten seconds. At this rate how many minutes will it take to stamp 24,408 bottle caps?
tigry1 [53]

Answer:


Step-by-step explanation:

There are 60 seconds in a minute. The machine stamps 36 caps in 10 seconds. 36X6=216 caps per minute.

24,408/216=113

It will take 113 minutes or 1 hour and 53 minutes

6 0
2 years ago
Read 2 more answers
Which two solids have the same number of faces?
Vera_Pavlovna [14]

We need the pictures

6 0
3 years ago
Read 2 more answers
Layton made 117$ for 9 hours of work.at the same rate,how many hours would she have to work to make $65?
Bogdan [553]

Since she makes $13 per hour, she would have to work 5 hours to make $65.

7 0
3 years ago
DNA molecules consist of chemically linked sequences of the bases adenine, guanine, cytosine and thymine, denoted A, G, C and T.
Dmitry [639]

Answer:

1. See the attached tree diagram (64 different sequences); 2. 64 codons; 3. 8 codons; 4. 24 codons consist of three different bases.

Step-by-step explanation:

The main thing to solve this kind of problem, it is to know if the pool of elements admits <em>repetition</em> and if the <em>order matters</em> in the sequences or collections of objects that we can form.

In this problem, we have the bases of the DNA molecule, namely, adenine (A), thymine (T), guanine (G) and cytosine (C) and they may appear in a sequence of three bases (codon) more than once. In other words, <em>repetition is allowed</em>.

We can also notice that <em>order matters</em> in this problem since the position of the base in the sequence makes a difference in it, i.e. a codon (ATA) is different from codon (TAA) or (AAT).

Then, we are in front of sequences that admit repetitions and the order they may appear makes a difference on them, and the formula for this is as follows:

\\ Sequences\;with\;repetition = n^{k} (1)

They are sequences of <em>k</em> objects from a pool of <em>n</em> objects where the order they may appear matters and can appeared more than once (repetition allowed).

<h3>1 and 2. Possible base sequences using tree diagram and number of possible codons</h3>

Having all the previous information, we can solve this question as follows:

All possible base sequences are represented in the first graph below (left graph) and are 64 since <em>n</em> = 4 and <em>k</em> = 3.

\\ Sequences\;with\;repetition = 4^{3} = 4*4*4 = 64

Looking at the graph there are 4 bases * 4 bases * 4 bases and they form 64 possible sequences of three bases or codons. So <em>there are 64 different codons</em>. Graphically, AAA is the first case, then AAT, the second case, and so on until complete all possible sequences. The second graph shows another method using a kind of matrices with the same results.

<h3>3. Cases for codons whose first and third bases are purines and whose second base is a pyrimidine</h3>

In this case, we also have sequences with <em>repetitions</em> and the <em>order matters</em>.

So we can use the same formula (1) as before, taking into account that we need to form sequences of one object for each place (we admit only a Purine) from a pool of two objects (we have two Purines: A and G) for the <em>first place</em> of the codon. The <em>third place</em> of the codon follows the same rules to be formed.

For the <em>second place</em> of the codon, we have a similar case: we have two Pyrimidines (C and T) and we need to form sequences of one object for this second place in the codon.

Thus, mathematically:

\\ Sequences\;purine\;pyrimidine\;purine = n^{k}*n^{k}*n^{k} = 2^{1}*2^{1}*2^{1} = 8

All these sequences can be seen in the first graph (left graph) representing dots. They are:

\\ \{ATA, ATG, ACA, ACG, GTA, GTG, GCA, GCG\}

The second graph also shows these sequences (right graph).

<h3>4. Possible codons that consist of three different bases</h3>

In this case, we have different conditions: still, order matters but no repetition is allowed since the codons must consist of three different bases.

This is a case of <em>permutation</em>, and the formula for this is as follows:

\\ nP_{k} = \frac{n!}{n-k}! (2)

Where n! is the symbol for factorial of number <em>n</em>.

In words, we need to form different sequences (order matters with no repetition) of three objects (a codon) (k = 3) from a pool of four objects (n = 4) (four bases: A, T, G, and C).

Then, the possible number of codons that consist of three different bases--using formula (2)--is:

\\ 4P_{3} = \frac{4!}{4-3}! = \frac{4!}{1!} = \frac{4!}{1} = 4! = 4*3*2*1 = 24

Thus, there are <em>24 possible cases for codons that consist of three different bases</em> and are graphically displayed in both graphs (as an asterisk symbol for left graph and closed in circles in right graph).

These sequences are:

{ATG, ATC, AGT, AGC, ACT, ACG, TAG, TAC, TGA, TGC, TCA, TCG, GAT, GAC, GTA, GTC, GCA, GCT, CAT, CAG, CTA, CTG, CGA, CGT}

<h3 />

6 0
3 years ago
Other questions:
  • Find the value of X, can someone help me?
    9·1 answer
  • Multiply (x-3)(4x+2) using destributive property select the answer choice showing up he correct distribution
    14·2 answers
  • What is the value of h in the equation 3h-4=15+2?
    7·1 answer
  • linda thinks of a two digit number. the sum of the digits is 8. if she reverses the digits, the new number is 26 greater than he
    7·1 answer
  • Angie, blake, carlos, and daisy went running. angie ran 1/3 mile, blake ran 3/5 mile, carlos ran 7/10 mile, and daisy ran 1/2 mi
    14·1 answer
  • 1/2*40=2x+8 what is the answer
    15·2 answers
  • Help ASAP<br><br> Brian ran 4 1/4 miles in 3/4 of an hour. How fast was brian running.
    7·2 answers
  • The scale on a map in 0.5 in.:10mi. If the map shows that the distance from Barkley to Winston is 4.5 in., what is the actual di
    15·1 answer
  • -3 &lt; -1, subtract both sides by 3
    10·1 answer
  • PLEASE HELP!!!!!!!!!!!! WILL MARK BAINLIEST!
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!