Answer:
The period is
Explanation:
From the question we are told that
The extension of the spring is
The first weight applied is
The second weight applied is
The second extension is
The spring constant of the spring is mathematically evaluated as
substituting values
We are told that
19 N extended the spring to 33 m
Then W N will extended it by 17 m
Therefore
Generally the period of the oscillation is mathematically represented as
where M is the mass of the W which is mathematically evaluated as
substituting values
Answer:
1. A non example of a constant in physics is a value that changes. For example, the temperature of Hong Kong, let's say, is not a constant, since it changes and does not stay at the same value. It gets higher in the summer and lower in the winter.
2. An example of a constant in physics would be the gravitational acceleration of the Earth. Since the Earth's mass' changes is negligible when compared with the overall mass of the Earth (unless something big happens, of course, like a meteor or asteroid), the gravitational acceleration on Earth is largely unchanged, even constant from our viewpoint.
Explanation:
Hope this helped!
Answer:
Explanation:
Recall that density is defined as and that relative uncertainty is defined as where is the uncertainty in the measure and a the measure, To find the uncertainty when two physical quantities are divided, their relative uncertainties are added and then multiplied with the division result of the quantities.
We have:
To find the percent uncertainty, we multiply the relative uncertainty by 100%.
Answer:
The total frictional force is 358.0 newtons
Explanation:
Power is the amount of average work (W) an object does on a period of time (Δt):
Remember average work is average force (F) times displacement (Δs):
but displacement over time is average speed , then:
(1)
That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:
Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308 = , then: