Answer:
The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.
Explanation:
Given that,
The respective indices of refraction for the blue light and the red light are 1.4636 and 1.4561.
A ray of light consisting of blue light (wavelength 480 nm) and red light (wavelength 670 nm) is incident on a thick piece of glass at 80 degrees.
We need to find the angular separation between the refracted red and refracted blue beams while they are in the glass.
Using Snell's law for red light as :
![n_1\sin\theta_1=n_2\sin\theta_2\\\\\theta_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta_2=\sin^{-1}((\dfrac{1}{1.4561})\sin(80))\\\\\theta_2=42.555](https://tex.z-dn.net/?f=n_1%5Csin%5Ctheta_1%3Dn_2%5Csin%5Ctheta_2%5C%5C%5C%5C%5Ctheta_2%3D%5Csin%5E%7B-1%7D%28%28%5Cdfrac%7Bn_2%7D%7Bn_1%7D%29%5Csin%5Ctheta_1%29%5C%5C%5C%5C%5Ctheta_2%3D%5Csin%5E%7B-1%7D%28%28%5Cdfrac%7B1%7D%7B1.4561%7D%29%5Csin%2880%29%29%5C%5C%5C%5C%5Ctheta_2%3D42.555)
Again using Snell's law for blue light as :
![n_1\sin\theta_1=n_2\sin\theta'_2\\\\\theta'_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta'_2=\sin^{-1}((\dfrac{1}{1.4636 })\sin(80))\\\\\theta'_2=42.283](https://tex.z-dn.net/?f=n_1%5Csin%5Ctheta_1%3Dn_2%5Csin%5Ctheta%27_2%5C%5C%5C%5C%5Ctheta%27_2%3D%5Csin%5E%7B-1%7D%28%28%5Cdfrac%7Bn_2%7D%7Bn_1%7D%29%5Csin%5Ctheta_1%29%5C%5C%5C%5C%5Ctheta%27_2%3D%5Csin%5E%7B-1%7D%28%28%5Cdfrac%7B1%7D%7B1.4636%20%7D%29%5Csin%2880%29%29%5C%5C%5C%5C%5Ctheta%27_2%3D42.283)
The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.
Answer:
The law of conservation of energy can be seen in these everyday examples of energy transference: Water can produce electricity. Water falls from the sky, converting potential energy to kinetic energy. ... The cue ball loses energy because the energy it had has been transferred to the 8 ball, so the cue ball slows down.
The distance between Mars and the Sun in the scale model would be 1140 m
Explanation:
In this scale model, we have:
represents an actual distance of
![d_1 = 1.0\cdot 10^5 km](https://tex.z-dn.net/?f=d_1%20%3D%201.0%5Ccdot%2010%5E5%20km)
The actual distance between Mars and the Sun is 228 million km, therefore
![d_2=228\cdot 10^6 km](https://tex.z-dn.net/?f=d_2%3D228%5Ccdot%2010%5E6%20km)
On the scale model, this would corresponds to a distance of
.
Therefore, we can write the following proportion:
![\frac{x_1}{d_1}=\frac{x_2}{d_2}](https://tex.z-dn.net/?f=%5Cfrac%7Bx_1%7D%7Bd_1%7D%3D%5Cfrac%7Bx_2%7D%7Bd_2%7D)
And solving for
, we find:
![x_2=\frac{x_1 d_2}{d_1}=\frac{(50)(228\cdot 10^6)}{1\cdot 10^5}=1.14\cdot 10^5 cm = 1140 m](https://tex.z-dn.net/?f=x_2%3D%5Cfrac%7Bx_1%20d_2%7D%7Bd_1%7D%3D%5Cfrac%7B%2850%29%28228%5Ccdot%2010%5E6%29%7D%7B1%5Ccdot%2010%5E5%7D%3D1.14%5Ccdot%2010%5E5%20cm%20%3D%201140%20m)
Learn more about distance:
brainly.com/question/3969582
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