Answer:
The correct option is;
Force of Friction
Explanation:
As coach Hogue rode his motorcycle round in circle on the wet pavement, the motorcycle and the coach system tends to move in a straight path but due to intervention by the coach they maintain the circular path
The motion equation is
v = ωr and we have the centripetal acceleration given by
α = ω²r and therefore centripetal force is then
m×α = m × ω²r = m × v²/r
The force required to keep the coach and the motorcycle system in their circular path can be obtained by the impressed force of friction acting towards the center of the circular motion.
That is -300 J, because the work = the force times the distance. When the distance is a positive value when it is going down, the distance is a negative value when it is going up. The only thing that change is the minus, the absolute value of the work remains the same
Explanation:
You have already determined the components of the known forces so I won't repeat your work here. Since the resultant force 
and F1 are completely along the x-axis, we can conclude that
We can now solve for the magnitude of 
The angle 
is then
or
Answer:
contour lines
Explanation:
Contour lines is a map feature which help to indicate region of equal height in a map.
In a map, contour lines are usually drawn in irregular circles repeatedly, until the elevations of the region are fully represented.
The inner part of the contour lines usually denote high elevation while the outter contour lines usually denote lower elevation.
Therefore the map feature that best indicates whether two regions have the same elevation is contour lines.
Answer:
Explanation:
given,
diameter of inlet = 11.2 cm
r₁ = 5.6 cm
r₁ = 0.056 m ∵ 1 cm = 0.01 m
speed of inlet = 5 m/s
diameter of outlet = 17.5 cm
r₂ = 8.75 cm
r₂ = 0.0875 m ∵ 1 cm = 0.01 m
speed of outlet = ?
using continuity equation
A₁ v₁ = A₂ v₂
π r₁² v₁ = π r₂² v₂
Velocity of liquid at the outlet of the tube is equal to 3.2 m/s
