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zhenek [66]
3 years ago
11

Which of the following distinguishes a nuclear reaction from a chemical reaction? a.It involves atoms.

Chemistry
2 answers:
MissTica3 years ago
7 0
The option that distinguishes a nuclear reaction from a chemical reaction is D. there is a change in the nucleus.
During a nuclear reaction, two light nuclei combine in order to create a new, heavier one which is different than those two original ones and has additional particles that it didn't have originally. This is what makes the difference between these two reactions.
hjlf3 years ago
7 0

Answer: Option (D) is the correct answer.

Explanation:

In a nuclear reaction, subparticles like protons and neutrons are involved in a reaction. So, basically changes in the nucleus of an atom occurs.

This is because in a nuclear reaction either two nuclei combine to form a larger nuclei different from its parent atom or nucleus of an atom dissociates into different atoms.

For example, ^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n is a nuclear fusion reaction.

Whereas in a chemical reaction exchange of electrons occur or we can say electrons are involved in chemical reactions.

For example, 2Na(s) + Cl_{2}(g) \rightarrow 2NaCl

Thus, we can conclude that out of the given options, there is a change in the nucleus distinguishes a nuclear reaction from a chemical reaction.

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(1) The solubility of Salt AB2(S) IS 5mol/dm^3.
Svetlanka [38]

Answer:

a. Ksp = 4s³

b. 5.53 × 10⁴ mol³/dm⁹

Explanation:

a. Obtain an expression for the solubility product of AB2(S),in terms of s.

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AB₂ ⇄ A²⁺ + 2B⁻

Since 1 mole of AB₂ gives 1 mole of A and 2 moles of B, we have the mole ratio as

AB₂ ⇄ A²⁺ + 2B⁻

1 : 1 : 2

Since the solubility of AB₂ is s, then the solubility of A is s and that of B is 2s

So, we have

AB₂ ⇄ A²⁺ + 2B⁻

[s]        [s]    [2s]

So, the solubility product Ksp = [A²⁺][B⁻]²

= (s)(2s)²

= s(4s²)

= 4s³

b. Calculate the Ksp of AB₂, given that solubility is 2.4 × 10³ mol/dm³

Given that the solubility of AB is 2.4 × 10³ mol/dm³ and the solubility product Ksp = [A²⁺][B⁻]² = 4s³ where s = solubility of AB = 2.4 × 10³ mol/dm³

Substituting the value of s into the equation, we have

Ksp = 4s³

= 4(2.4 × 10³ mol/dm³)³

= 4(13.824 × 10³ mol³/dm⁹)

= 55.296 × 10³ mol³/dm⁹

= 5.5296 × 10⁴ mol³/dm⁹

≅ 5.53 × 10⁴ mol³/dm⁹

Ksp = 5.53 × 10⁴ mol³/dm⁹

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