Answer:
90 °C
Explanation:
First, we must know the specific heat capacity of water, which is defined as the energy required to heat 1 gram of water by one degree Celsius. The specific heat capacity of water is 1 cal·g⁻¹°C⁻¹.
The equation we will use is Q = mcΔt, where Q is the heat energy, m is the mass, c is the specific heat capacity, and Δt is the temperature change. We will rearrange the equation to solve for Δt and substitute the values:
Δt = Q / (mc) = (90 kcal)(1000 cal/kcal) / (1 kg)(1000 g/kg)(1 cal·g⁻¹°C⁻¹) = 90 °C
Answer:
The rate equation for this reaction:
![R=k[NH_3]^0](https://tex.z-dn.net/?f=R%3Dk%5BNH_3%5D%5E0)
Explanation:
Decomposition of ammonia:

Rate law of the can be written as;
![R=k[NH_3]^x](https://tex.z-dn.net/?f=R%3Dk%5BNH_3%5D%5Ex)
1) Rate of the reaction , when ![[NH_3]=2.0\times 10^{-3} M](https://tex.z-dn.net/?f=%5BNH_3%5D%3D2.0%5Ctimes%2010%5E%7B-3%7D%20M)
..[1]
2) Rate of the reaction , when ![[NH_3]=4.0\times 10^{-3} M](https://tex.z-dn.net/?f=%5BNH_3%5D%3D4.0%5Ctimes%2010%5E%7B-3%7D%20M)
..[2]
[1] ÷ [2]
![\frac{1.5\times 10^{-6}M/s}{1.5\times 10^{-6}M/s}=\frac{k[2.0\times 10^{-3}M]^x}{k[4.0\times 10^{-3}M]^x}](https://tex.z-dn.net/?f=%5Cfrac%7B1.5%5Ctimes%2010%5E%7B-6%7DM%2Fs%7D%7B1.5%5Ctimes%2010%5E%7B-6%7DM%2Fs%7D%3D%5Cfrac%7Bk%5B2.0%5Ctimes%2010%5E%7B-3%7DM%5D%5Ex%7D%7Bk%5B4.0%5Ctimes%2010%5E%7B-3%7DM%5D%5Ex%7D)
On solving for x , we get ;
x = 0
The rate equation for this reaction:
![R=k[NH_3]^0](https://tex.z-dn.net/?f=R%3Dk%5BNH_3%5D%5E0)
<span>(3.5 lb Ti) x (453.592 g Ti / 1 lb Ti) x (1 cm^3 Ti / 4.51 g Ti) x 0.0610237 in^3 / 1 cm^3) = 21 in^3 Ti.
Use factor label method to cancel out units and make sure to cancel out the units to the solution, which in this case is volume of titanium in cubic inches. We only keep two digits because the original numbers use have two sig figs as the least amount when doing multiplication or division.</span>
To solve this, we should follow order of operations. To start, we should multiply the values inside of the parentheses.
(34.6785*5.39)+435.12
186.917115+435.12
Now, we should add the 2 values we are left with together.
186.917115
<span><u>+435.120000</u>
</span> 622.037115
Using the math above, we can see that this expression is equal to 622.037115.

<em><u>The Rutherford model shows that an atom is mostly empty space, with electrons orbiting a fixed, positively charged nucleus in set, predictable paths.</u></em>