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weeeeeb [17]
3 years ago
10

The mean of three numbers x, y and z is 6 and the mean of five numbers x, y, z, a and b is 8.

Mathematics
1 answer:
aksik [14]3 years ago
7 0

Answer:

11

Step-by-step explanation:

To find the mean of a set of numbers, we add all of the numbers together and divide the sum by the size of the set. For that first set, we have three numbers, x, y and z, so the equation for their mean would be

\dfrac{x+y+z}{3}=6

We can rearrange this equation by multiplying both sides by 3, getting the equivalent equation

x+y+z=18\ \ \ \ (1)

Let's do the same thing for the second mean:

\dfrac{x+y+z+a+b}{5}=8

x+y+z+a+b=40\ \ \ \ (2)

With the two equations we've obtained, we can subtract (1) from (2) to get rid of x, y, and z, leaving us with

a+b=22

To find the mean of a and b now, all we have to do is divide both sides of the equation by 2, and we see that

\dfrac{a+b}{2}=11

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Answer:

x\geq 19/6

Step-by-step explanation:

1. Multiply both sides by 6 (the LCM of 6,3)

5/2 + 3-x <= 2(x-2)

2. Simplify 5/2+3-x to 11/2-x

11/2 - x<=2 (x-2)

3. Expand.

11/2-x<= 2x-4

4. Add x to both sides.

11/2<= 2x-4+x

5. Simplify 2x-4+x to 3x-4.

11/2<=3x-4

6. Add 4 to both sides.

11/2+4<=3x

7. Simplify 11/2+4 to 19/2

19/2<=3x

8. Divide both sides by 3

19/2 /3 <=x

9. Simplify 19/2 /3 to 19/2*3

19/2*3<=x

10. Simplify 2*3 to 6

19/6<=x

11. Switch sides.

x>= 19/6

Hope this helps!

4 0
3 years ago
ΔABC is a right triangle in which is a right angle, AB = 1, AC = 2, and BC = .
ollegr [7]
We are asked to solve for the measurement of side BC in the given right triangle ΔABC and other side measurements were also given such as AB=1 and AC = 2. Since this is a right triangle, we can use and apply the Pythagorean theorem c²= a² + b² and the solution is shown below:
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2² = 1² + BC²
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BC = √3
BC = 1.732

The answer for the length of BC is 1.732 units.
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3 years ago
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Step-by-step explanation:

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