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weeeeeb [17]
3 years ago
10

The mean of three numbers x, y and z is 6 and the mean of five numbers x, y, z, a and b is 8.

Mathematics
1 answer:
aksik [14]3 years ago
7 0

Answer:

11

Step-by-step explanation:

To find the mean of a set of numbers, we add all of the numbers together and divide the sum by the size of the set. For that first set, we have three numbers, x, y and z, so the equation for their mean would be

\dfrac{x+y+z}{3}=6

We can rearrange this equation by multiplying both sides by 3, getting the equivalent equation

x+y+z=18\ \ \ \ (1)

Let's do the same thing for the second mean:

\dfrac{x+y+z+a+b}{5}=8

x+y+z+a+b=40\ \ \ \ (2)

With the two equations we've obtained, we can subtract (1) from (2) to get rid of x, y, and z, leaving us with

a+b=22

To find the mean of a and b now, all we have to do is divide both sides of the equation by 2, and we see that

\dfrac{a+b}{2}=11

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the equation of the axis of symmetry is x=h

In this problem

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so the x-coordinate of the vertex is h=6

<u>Convert the quadratic equation in vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-10=\frac{1}{4} x^{2} +bx

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f(x)-10=\frac{1}{4}(x^{2} +4bx)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-10+b^{2}=\frac{1}{4}(x^{2} +4bx+4b^{2})

Rewrite as perfect squares

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remember that

h=6

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