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solmaris [256]
3 years ago
7

A boat traveled at a constant speed for 22 hours, covering a total distance of 618.7 kilometers. To the nearest tenth of a kilom

eter per hour, how fast was it going? kilometers per hour
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
4 0

Answer:

28.1 kilometers/hour

Step-by-step explanation:

618.7 kilometers / 22 hours = 28.1 kilometers/hour

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The entry ticket to a local football game costs $10 for an adult and $5 for a child. A group of 100 people paid an entry fee of
-Dominant- [34]

Answer: Adults = 58

Children = 42

Step-by-step explanation:

Let adults be denoted as a

Let Children be denoted as c

a + c = 100 ...... i

10a + 5c = 710 ...... ii

Multiply I by 5

Multiply ii by 1

5a + 5c = 500 ...... iii

10a + 5c = 710 ...... iv

Subtract iii from iv

5a = 210

a = 210/5

a = 42

Since a + c = 100

c = 100 - 42 = 58.

Adults = 58

Children = 42

8 0
2 years ago
The expression above can also be written in the form of
gladu [14]

Answer:

a= 7

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Step-by-step explanation:

8 0
3 years ago
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Tomtit [17]
The questions are asking what percent it changed, not what amount.
6 0
3 years ago
The weights of boxes of candies produced in a factory are normally distributed with a mean weight of 16 oz and a standard deviat
JulijaS [17]
Let the required weight be X, then
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3 0
3 years ago
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Ian puts 300.00 into an account to use for school expenses the account earns 6%interest compounded annually how much will be in
romanna [79]

This problem is about componded interest. The formula for compounded interest is:

\begin{gathered} \text{Amount}=\text{Initial}\cdot(1+r)^t \\ \text{Where,} \\ \text{Amount is the total acumulative at time t.} \\ \text{Initial is the initial amount, at t=0} \\ r\text{ is the interest in decimal number.} \\ t\text{ is the time accordingly the interest, in this case is in years.} \end{gathered}

In this case, Initial = 300, r = 0.06 and t=10 so the total amount in the account after 10 years is:

\begin{gathered} \text{Amount}=300\cdot(1+0.06)^{10} \\ \text{Amount}=300\cdot1.06^{10} \\ \text{Amount}=300\cdot1.79085 \\ \text{Amount}=537.255 \end{gathered}

The amount after 10 years is 573.26.

4 0
1 year ago
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