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elixir [45]
4 years ago
13

When water freezes, its volume increases by 9.05%. What force per unit area is water capable of exerting on a container when it

freezes? a)0.20 kPa
b)0.20 MPa
c)0.20 GPa
d)0.20 TPa
Physics
1 answer:
AnnZ [28]4 years ago
6 0

Answer:

The Pressure is 0.20 MPa.

(b) is correct option.

Explanation:

Given that,

Change in volume = 9.05%

{tex]\dfrac{\Delta V}{V_{0}}=0.0905[/tex]

We know that.

The bulk modulus for water

B=0.20\times10^{10}\ N/m^2

We need to calculate the pressure difference

Using formula bulk modulus formula

B=\Delta P\dfrac{V_{0}}{\Delta V}

\Delta P=B\dfrac{\Delta V}{V_{0}}

\Delta P=0.2\times10^{10}\times0.0905

\Delta P=0.2\times10^{6}\ Pa

\Delta P=0.20 MPa

Hence, The Pressure is 0.20 MPa.

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Georgie was pulling her brother (of mass 16 kg) in a 9.4 kg sled with a constant force of 39 N for one block (128 m). How much w
Genrish500 [490]

Answer:

4992 J

Explanation:

Force, F = 39 N

Distance, s = 128 m

Work done = force x distance

W = 39 x 128

W = 4992 J

Thus, the work done is 4992 J.

7 0
4 years ago
8) A plastic rod, initially uncharged, is rubbed with wool and obtains a charge of 10 C. What is the charge on the wool after ru
LenKa [72]

Answer:

The charge on the wool after rubbing is - 10 C

Explanation:

Every uncharged body is electrically neutral, if the plastic rod acquires 10 Coulombs of charge after been rubbed with wool, then the wool will be left with an equal but opposite charge. This shows that the initial charge on the wool is 10 protons and 10 electrons and when the plastic acquires 10 C (10 protons), the wool will be left with excess 10 electrons.

Therefore, the charge on the wool after rubbing is - 10 C (negative 10 Coulombs).

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4 years ago
What is the correct definition of opinion polls? Question 2 options:
Ainat [17]

Answer:

i think the answer is D. surveys that ask people questions about specific topics, issues, or individuals

plz mark me as brainliest if this helped :)

5 0
3 years ago
The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is j. (formula: )
andreyandreev [35.5K]
1/2 m V-squared = j. j = 25 joules.
3 0
3 years ago
Read 2 more answers
How long will it take a 2.3"x10^3 kg truck to go from 22.2 m/s to a complete stop if acted on by a force of -1.26x10^4 N.What wo
Greeley [361]

The stopping distance is 45.0 m

Explanation:

First of all, we find the acceleration of the truck, by using Newton's second law:

F=ma

where

F=-1.26\cdot 10^4 N is the net force on the truck

m=2.3\cdot 10^3 kg is the mass of the truck

a is its acceleration

Solving for a,

a=\frac{F}{m}=\frac{-1.26\cdot 10^4}{2.3\cdot 10^3}=-5.48 m/s^2

where the negative sign means the acceleration is opposite to the direction of motion.

Now, since the motion of the truck is at constant acceleration, we can apply the following suvat equation:

v^2-u^2=2as

where

v = 0 is the final velocity of the truck

u = 22.2 m/s is the initial velocity

a=-5.48 m/s^2 is the acceleration

s is the stopping distance

And solving for s,

s=\frac{v^2-u^2}{2a}=\frac{0-(22.2)^2}{2(-5.48)}=45.0 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0
4 years ago
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